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wel
2 years ago
11

In prolonged fasting conditions acetyl-coa generated from the breakdown of amino acids and fatty acids does not enter the citric

acid cycle in the liver, but acetyl-coa derived from ketone bodies can enter the citric acid cycle in the brain.
Chemistry
1 answer:
Brums [2.3K]2 years ago
7 0

In prolonged fasting conditions acetyl-coa generated from the breakdown of amino acids and fatty acids does not enter the citric acid cycle in the liver, but acetyl-coa derived from ketone bodies can enter the citric acid cycle in the brain. <u>Cholesterol is required in the diet.</u>

<h3>What is amino acids?</h3>

Amino acids are chemical molecules having side chains (R groups) unique to each amino acid as well as amino and carboxylic acid (CO2H) functional groups.

Every amino acid contains the elements carbon (C), hydrogen (H), oxygen (O), and nitrogen (N) (CHON); in addition, the side chains of cysteine and methionine contain sulfur (S), while the less frequent amino acid selenocysteine has selenium (Se). As of 2020, it is known that more than 500 naturally occurring amino acids make up the monomer units of peptides, including proteins.

Despite the fact that there are only 22 proteins, 20 of them have unique specified codons, and another two have unique coding mechanisms: All eukaryotes contain selenocysteine, and pyrrolysine is also present.

To learn more about amino acids from the given link:

brainly.com/question/21327676

#SPJ4

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How do I do this? What are the answers to the 5 questions shown?
frozen [14]

Answer:

1. C₃H₆O₃

2. C₆H₁₂

3. C₆H₂₄O₆

4. C₆H₆

5. N₂O₄

Explanation:

1. Determination of the molecular formula.

Empirical formula => CH₂O

Mass of compound = 90 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[CH₂O]ₙ = 90

[12 + (2×1) + 16]n = 90

[12 + 2 + 16]n = 90

30n = 90

Divide both side by 30

n = 90/30

n = 3

Molecular formula = [CH₂O]ₙ

Molecular formula = [CH₂O]₃

Molecular formula = C₃H₆O₃

2. Determination of the molecular formula.

Empirical formula => CH₂

Mass of compound = 84 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[CH₂]ₙ = 84

[12 + (2×1)]n = 84

[12 + 2]n = 84

14n = 84

Divide both side by 14

n = 84/14

n = 6

Molecular formula = [CH₂]ₙ

Molecular formula = [CH₂]₆

Molecular formula = C₆H₁₂

3. Determination of the molecular formula.

Empirical formula => CH₄O

Mass of compound = 192 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[CH₄O]ₙ = 192

[12 + (4×1) + 16]n = 192

[12 + 4 + 16]n = 192

32n = 192

Divide both side by 32

n = 192/32

n = 6

Molecular formula = [CH₄O]ₙ

Molecular formula = [CH₄O]₆

Molecular formula = C₆H₂₄O₆

4. Determination of the molecular formula.

Empirical formula => CH

Mass of compound = 78 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[CH]ₙ = 78

[12 + 1]n = 78

13n = 78

Divide both side by 13

n = 78/13

n = 6

Molecular formula = [CH]ₙ

Molecular formula = [CH]₆

Molecular formula = C₆H₆

5. Determination of the molecular formula.

Empirical formula => NO₂

Mass of compound = 92 g

Molecular formula =?

Molecular formula = n × Empirical formula = mass of compound

[NO₂]ₙ = 92

[14 + (2×16)]n = 92

[14 + 32]n = 92

46n = 92

Divide both side by 46

n = 92/46

n = 2

Molecular formula = [NO₂]ₙ

Molecular formula = [NO₂]₂

Molecular formula = N₂O₄

6 0
3 years ago
The mole fraction of nitrogen in the air is 0.7808. this means that 78.08% of the molecules in the air are nitrogen. when the at
Pachacha [2.7K]

Answer:

p = \boxed{\text{593 torr}}

Explanation:

For this question, we must use Dalton's Law of Partial Pressures:

The partial pressure of a gas in a mixture of gases equals its mole fraction times the total pressure:

p = \chi p_{\text{tot}}

Data:

χ = 0.7808

p_{\text{tot}} = \text{ 760 torr}

Calculation:

p = 0.7808 \times \text{ 760 torr}\\\\p= \boxed{\textbf{593 torr}}

7 0
2 years ago
I need it done assapp
Alja [10]

Answer:

water molecules

Explanation:

4 0
2 years ago
Read 2 more answers
HELPPP
Licemer1 [7]

Answer:

79 protons.

Explanation:

8 0
2 years ago
A sealed 1.0 L flask is charged with 0.500 mol of I2 and 0.500 mol of Br2. An equilibrium reaction ensues: I2 (g) + Br2 (g) ↔ 2I
Daniel [21]

Answer:  Thus the value of K_{eq} is 110.25

Explanation:

Initial moles of  I_2 = 0.500 mole

Initial moles of  Br_2 = 0.500 mole

Volume of container = 1 L

Initial concentration of I_2=\frac{moles}{volume}=\frac{0.500moles}{1L}=0.500M

Initial concentration of Br_2=\frac{moles}{volume}=\frac{0.500moles}{1L}=0.500M

equilibrium concentration of IBr=\frac{moles}{volume}=\frac{0.84mole}{1L}=0.84M [/tex]

The given balanced equilibrium reaction is,

                            I_2(g)+Br_2(g)\rightleftharpoons 2IBr(g)

Initial conc.              0.500 M     0.500 M             0  M

At eqm. conc.    (0.500-x) M      (0.500-x) M     (2x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[IBr]^2}{[Br_2]\times [I_2]}

K_c=\frac{(2x)^2}{(0.500-x)\times (0.500-x)}

we are given : 2x = 0.84 M

x= 0.42

Now put all the given values in this expression, we get :

K_c=\frac{(0.84)^2}{(0.500-0.42)\times (0.500-0.42)}

K_c=110.25

Thus the value of the equilibrium constant is 110.25

8 0
3 years ago
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