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Temka [501]
2 years ago
10

What Is the answers?

Chemistry
2 answers:
Yuki888 [10]2 years ago
5 0

Answer:

oxygen is responsible for rusting

Gala2k [10]2 years ago
4 0
Oxygen causes the metal can to rust
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Explain what happens to the average kinetic energy thermal energy and temperature of a substance when the particles in the subst
kkurt [141]
The average kinetic energy and thermal energy decreases, and the temperature decreases as well.
8 0
3 years ago
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Which of the following BEST describes a way in which water moves in the water cycle?
____ [38]

Answer: Its A or D                                                        

wish i had an actual answer sorry..  

6 0
3 years ago
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Of the molecules below, the bond in ________ is the most polar. of the molecules below, the bond in ________ is the most polar.
Goryan [66]
Polarity   is  classified by  the  difference  in  two  or  more  atoms that  is  the electronegativity  value (EN)
En  for  Fluorine =4.0,  Bromine=2.96 Chlorine =3.16  Hydrogen=2.1
for  the molecules
HF=4.0-2.I=1.9
HCl=3.16-2.1=1.06
Hbr=2.96-2.1=0.86
Hi=2.66-2.1=0.56
H2=2.1-2.1=0
from  the  EN  value above  HF  has  the  mast  highest  value  of  EN  hence  it  is  the  most  polar.
6 0
3 years ago
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A fossil was analyzed and determined to have a carbon-14 level that is 70 % that of living organisms. The half-life of C-14 is 5
Citrus2011 [14]

Answer: 2948

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

t_{\frac{1}{2}}=\frac{0.693}{k}

k=\frac{0.69}{t_{\frac{1}{2}}}=\frac{0.693}{5730}=1.21\times 10^{-4}years^{-1}

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant  = 1.21\times 10^{-4}years^{-1}

t = age of sample  = ?

a = let initial amount of the reactant  = 100

a - x = amount left after decay process = \frac{70}{100}\times 100=70

t=\frac{2.303}{1.21\times 10^{-4}}\log\frac{100}{70}

t=2948years

Thus the fossil is 2948 years old.

5 0
3 years ago
Find [cu2+] in a solution saturated with cu4(oh)6(so4) if [oh − ] is fixed at 2.3 ✕ 10−6 m. note that cu4(oh)6(so4) gives 1 mol
ki77a [65]
<span>

</span>Cu_4(OH)_6(SO_4)
<span>
You have OH-  conc = </span>2.3 ✕ 10−6 m
From the formula, you can observe the ratio of Cu2+ to OH- is  4 : 6 = 2:3

So, for 2.3 ✕ 10−6 m OH-
[Cu2+] = \frac{2}{3} \times 2.3 \times 10^{-6}

= 1.53  \times 10^{-6} &#10;

6 0
3 years ago
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