Answer:
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The given question is incomplete. The complete question is :
What volume of 0.160 M solution of KOH must be added to 550.0 mL of the acidic solution to completely neutralize all of the 0.150 M hydrochloric acid?
Answer: Volume in liters to three significant figures is 0.516 L
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is KOH
We are given:

Putting values in above equation, we get:
(1L=1000ml)
Thus volume in liters to three significant figures is 0.516 L
Answer:
2,341g of CuSO₄.5H₂O
Explanation:
It is possible to assume all loses water comes from CuSO₄.5H₂O. Thus:
0,8445g H₂O (1mol H₂O / 18,015g) = 0,04688 moles of water.
As 1 mole of contains 5 moles of water, moles of CuSO₄.5H₂O are:
0,04688 moles H₂O × (1 mole CuSO₄.5H₂O / 5 moles H₂O) = 9,38x10⁻³ moles of CuSO₄.5H₂O
The molecular mass of CuSO₄.5H₂O is 249,69g/mol. Thus, mass of 9,38x10⁻³ moles of CuSO₄.5H₂O is:
9,38x10⁻³ moles of CuSO₄.5H₂O × (249,69g / mol) =
<em>2,341g of CuSO₄.5H₂O </em>is the maximum quantity of CuSO₄.5H₂O that could be in the sample.
I hope it helps!
Tincture of iodine has antiseptic properties and is made by dissolving iodine crystals in alcohol.
<h3>What are antiseptics?</h3>
Antiseptics are substance which prevent or stops the growth of microorganisms.
Microorganisms have been known to cause diseases, therefore the application of antiseptics are useful to prevent diseases.
An example of an antiseptic is tincture of iodine.
Tincture of iodine is prepared by dissolving iodine crystals in alcohol.
In conclusion, antiseptics are useful in the prevention of diseases by microorganism. An example of an antiseptic is tincture of iodine.
Learn more about tincture of iodine at: brainly.com/question/3209701
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