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jok3333 [9.3K]
3 years ago
15

he Lewis structure for CO molecule contains Group of answer choices one double bond, one single bond, and twelve nonbonding elec

trons two double bonds and eight nonbonding electrons one triple bond and four nonbonding electrons two single bonds and twelve nonbonding electrons
Chemistry
1 answer:
zimovet [89]3 years ago
6 0

Answer:

One triple bond and four non bonding electrons

Explanation:

In considering the lewis structure of carbon monoxide, we must remember that the molecule contains a total of ten valence electrons. Four are the valence electrons that are present on the valence shell of carbon while six are the valence electrons on oxygen. Some of these valence electrons participate in bonding in the CO molecule.

Out of the six valence electrons on oxygen, two valence electrons participate in bonding with carbon while the other four electrons remain localized on the oxygen atom as two lone pairs of electrons.

Hence there are four nonbonding electrons in the lewis structure of CO as well as one triple bond.

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<u>Answer:</u> The correct answer is Option b.

<u>Explanation:</u>

The expression of elevation in boiling point is given as:

\Delta T_b=i\times k_b\times m

where,

\Delta T_b = Elevation in boiling point

i = Van't Hoff factor  

T_b = change in boiling point

k_b = boiling point constant

m = molality

For the given options:

<u>Option 1:</u>  0.100 m NaNO_3

Value of i = 2

So, molal concentration will be = (0.100)\times 2=0.200m

<u>Option 2:</u>  0.100 m Li_2SO_4

Value of i = 3

So, molal concentration will be = (0.100)\times 3=0.300m

<u>Option 3:</u>  0.200 m C_3H_8O_3

Value of i = 1  (for non-electrolytes)

So, molal concentration will be = (0.200)\times 1=0.200m

<u>Option 4:</u>  0.060 m Na_3PO_4

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As, the molal concentration of Li_2SO_4 is the highest, so its boiling point will be the highest.

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NaNO_3=C_3H_8O_3

Hence, the correct answer is Option b.

4 0
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Answer:

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