Molal concentration gives the number of moles dissolved in 1 kg of solution.
Molal concentration of H₂SO₄ is 2.88 mol/kg
the weight of H₂SO₄ in 1 kg - 2.88 mol x 98 g/mol = 282.2 g
The total weight of solution - 1000 g + 282.2 g = 1282.2 g
density of solution is 1.167 g/ml
We need to find how many moles are dissolved in 1 L.
We know the weight of the solution, using this we can calculate volume of the solution
volume of solution is - 1282.2 g / 1.167 g/mL = 1098.7 mL
The number of H₂SO₄ moles in 1.0987 L = 2.88 mol
Therefore in 1 L = 2.88 mol / 1.0987 L = 2.62 mol
Molarity of H₂SO₄ is 2.62 mol/L = 2.62 M
Answer:
a. What would be the expected pH if a Student A accidentally diluted 9.1 mL (instead of 9.0 mL) of the acid to 100 mL? = 2.7423
b. If student A measured the above calculated pH, what would be the resultant K of acetic acid given that they expected the acid to have an initial concentration of 0.18M. = 1.838 x 10 ∧-5
Explanation:
check the attached file for explanation.
A clear chemical compound.
Okay so molar mass is given, no. of moles is given and we have to calculate the weight or mass of the compound in gram.
the formula we will use here is= n=W/M
where n is no. of moles ,w is weight in gram which we have to find and M is molar mass or formula weight which is given.
so W=n x M
use this formula you'll get the answer
Answer:
oh sorry i cant but i might think the answer is adaptive but if not someone correct me and ill change this response hope that i could help
Explanation: