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sergiy2304 [10]
2 years ago
13

The pyramid shown has a height of 14 inches and a base area of 60 in2. Find the volume of the pyramid.

Mathematics
1 answer:
Kamila [148]2 years ago
8 0

Volume of pyramid is 280 in^{3}.

The pyramid has a height 14 inches and a base area of 60 in2.

What is volume?

Volume is a three - dimensional quantity that is used to measure the capacity of a solid shape.

Volume of the pyramid = Area base X \frac{height}{3}

                                    = 60.\frac{14}{3}

                                    = 280 in^{3}

So the volume of pyramid = 280 in^{3}

Learn more about the Volume visit:

https://brainly.in/question/609711

#SPJ1

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Answer:

  h₁(t) = -16t² +110

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Put the given initial height into the given formula. That will give the requested function. If the function name is supposed to be h₁(t), then rename it.

  f(t) = -16t² +110 . . . . . . h = 110, the initial height

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A parabola can be drawn given a focus of (8, -1)(8,−1) and a directrix of y=-11y=−11. Write the equation of the parabola in any
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(x - 8)² = 20(y + 6)

Step-by-step explanation:

The focus of the parabola is (8,-1) and the equation of the directrix is y = - 11.

So, the parabola opens up and the axis of symmetry is x = 8 line.

Now, the axis of symmetry and the directrix meet at the point (8,-11).

So, the vertex of the parabola will be the midpoint of (8,-1) and (8,-11) i.e. (8,-6).

Now, half of the distance between the focus and the directrix is = a = \frac{11 - 1}{2} = 5 units.

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10% of the downtown residents of a town in the Plains live in mobile homes. Based on data from past tornadoes, if a tornado goes
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The probability a person will not live in a mobile home if they do not die as a result of the tornado is 0.9265.

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Denote the events as follows:

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<em>Y</em> = a person dies as a result of tornado.

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P(X)=0.10\\P(Y|X) = 0.30\\P(Y|X^{c})=0.02\\

Compute the value of P(Y^{c}|X^{c}) as follows:

P(Y^{c}|X^{c})=1-P(Y|X^{c})\\=1-0.02\\=0.98

Compute the probability that a person dies as a result of tornado as follows:

P(Y)=P(Y|X)P(X)+P(Y|X^{c})P(X^{c})\\=(0.30\times0.10)+(0.02\times(1-0.10))\\=0.03+0.018\\=0.048

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The distance between these points is 3.4 units

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