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inysia [295]
2 years ago
12

How many terms are in expression 9+14d+5w+7

Mathematics
1 answer:
tamaranim1 [39]2 years ago
4 0

9514 1404 393

Answer:

  4

Step-by-step explanation:

The terms are separated by addition/subtraction symbols. There are 4 terms.

With parentheses around each term, you have ...

  (9) + (14d) + (5w) + (7) . . . . 4 terms

_____

The two constant terms can be combined to give an expression with 3 terms:

  14d +5w +16

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A 29-foot rope is cut into two pieces. The longer piece is 2 feet longer than twice the shorter piece. How long is each piece?
Sati [7]

Answer:

20 is the longer piece, 9 is the shorter piece

Step-by-step explanation:

9*2=18

18+2=20

20+9=29

5 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B2%7D%20%20%5Ctimes%20%20-%202%20%2B%20%20%5Cfrac%7B1%7D%7B3%7D%20%20%5Ctim
WINSTONCH [101]
<h3>Here is your Answer </h3>

\frac{1}{2} \times - 2 + \frac{1}{3} \times - 5 \\  \\  = \frac{1}{ \cancel2} \times  \cancel{- 2} + \frac{1}{3} \times - 5 \\  \\  = 1 \times  - 1 +  \frac{1}{3}  \times  - 5 \\  \\  =  - 1 + ( -  \frac{5}{3} ) \\  \\   =  - 1 -  \frac{5}{3}  \\  \\  =  \frac{ - 3 - 5}{3}  \\  \\  =  \frac{ - 8}{3}  =  - 2 \frac{2}{3}

<h3>Hope This Helps You</h3>

8 0
3 years ago
What is the longest flagpole ( in whole feet) that could be shipped in a box that measures 2ft by 2 ft by 12 ft
creativ13 [48]
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3 0
3 years ago
What is the length of the missing base of the trapezoid?<br><br> 3 in<br> 8 in<br><br> Area= 21 in2
DerKrebs [107]

its 8...

3 on left, 3 on right 8 on top, 8 on bottom

8 0
3 years ago
Please show the working and answer. you can take a picture for the working.
baherus [9]

Answer:

(a) The area of the triangle is approximately 39.0223 cm²

(b) ∠SQR is approximately 55.582°

Step-by-step explanation:

(a) By sin rule, we have;

SQ/(sin(∠SPQ)) = PQ/(sin(∠PSQ)), which gives;

5.4/(sin(52°)) = 6.8/(sin(∠PSQ))

∴ (sin(∠PSQ)) = (6.8/5.4) × (sin(52°)) ≈ 0.9923

∠PSQ = sin⁻¹(0.9923) ≈ 82.88976°

Similarly, we have;

5.4/(sin(52°)) = SP/(sin(180 - 52 - 82.88976))

Where, 180 - 52 - 82.88976 = ∠PQS = 45.11024

SP = 5.4/(sin(52°))×(sin(180 - 52 - 82.88976)) ≈ 4.8549

Given that RS : SP = 2 : 1, we have;

RS = 2 × SP = 2 × 4.8549 ≈ 9.7098

We have by cosine rule, \overline {RQ}² =  \overline {SQ}² +  \overline {SR}² - 2 × \overline {SQ} × \overline {SR} × cos(∠QSR)

∠QSR and ∠PSQ are supplementary angles, therefore;

∠QSR = 180° - ∠PSQ = 180° - 82.88976° = 97.11024°

∠QSR = 97.11024°

Therefore;

\overline {RQ}² =  5.4² +  9.7098² - 2 ×  5.4×9.7098× cos(97.11024)

\overline {RQ}² ≈ 136.42

\overline {RQ} = √(136.42) ≈ 11.6799

The area of the triangle = 1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

By substituting the values, we have;

1/2 ×\overline {PQ} × \overline {PR} × sin(∠SPQ)

1/2 × 6.8 × (4.8549 + 9.7098) × sin(52°) ≈ 39.0223 cm²

The area of the triangle ≈ 39.0223 cm²

(b) By sin rule, we have;

\overline {RS}/(sin(∠SQR)) = \overline {RQ}/(sin(∠QSR))

By substituting, we have;

9.7098/(sin(∠SQR)) = 11.6799/(sin(97.11024))

sin(∠SQR) = 9.7098/(11.6799/(sin(97.11024))) ≈ 0.82493

∠SQR = sin⁻¹(0.82493) ≈ 55.582°.

8 0
3 years ago
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