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snow_tiger [21]
2 years ago
14

Calculate the energy of a photon emitted when an electron in a hydrogen atom undergoes a transition from =6 to =1.

Physics
1 answer:
scoundrel [369]2 years ago
5 0

When an electron in a hydrogen atom transitions from the state of n=6 to n=1, a photon with an energy of 13.2 eV is released.

<h3>What components make up a photon?</h3>
  • A photon is a microscopic particle that is part of electromagnetic radiation waves.
  • Maxwell demonstrated that photons are merely electric fields flowing through space.
  • A single photon can trigger a response from sensors in the retina.
<h3>What is the difference between an electron and a photon?</h3>
  • Photons and electrons. One of the fundamental quantum-mechanical particles is an electron, although photons also exist and have entirely distinct properties.
  • While the electron is a subatomic particle found in every atom, the photon is a sort of elementary particle that serves as an energy carrier.

learn more about photon here

brainly.com/question/15946945

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Given theta = 7pi/6, find (sec theta, cos theta) ...?
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There is an identity of sin(2pi-x) = -sin(x) and cos(2pi-x) = cos(x). This is what we are going to use. 


<span>(7pi/6) = (2pi)-(pi/6)

 </span>
Therefore: 
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1) sec(7pi/6) = 1/cos(2pi-(pi/6)) = 1/cos(pi/6) = 2sqrt(3)/3 
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<span>2) cos(7pi/6) = cos(pi/6) = sqrt(3)/2


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