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3 years ago

Help Quick!!!!

Physics

2 answers:

jarptica [38.1K]3 years ago

8 0

I’m unsure of the answer, but it is not b.

Sloan [31]3 years ago

6 0

Um uh uh um C ITS C WAIT NO A YUH ITS A THEY ERODE ROCKS

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Why is physical science important

Murrr4er [49]

"Traditionally, physical science courses are categorized into four areas: physics, chemistry, earth sciences, and space sciences. It is important to understand that the arbitrary divisions of specialized knowledge are integrated into a basic overview of the physical laws that govern our universe." - Cameron University

3 0

4 years ago

A stiff wire 50.0 cm long is bent at a right angle in the middle. One section lies along the z axis and the other is along the l

zloy xaker [14]

Answer:

Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis

Explanation:

The stiff wire 50.0cm long bent at a right angle in the middle

One section lies along the z axis and the other is along the line y=2x in the xy plane

$\frac{y}{x} = 2$

tan θ = 2

Therefore,

slope m = tan θ = y / x

$\theta=\tan^-^1(2)=63.4^0$

Then length of each section is 25.0cm

so, length vector of the wire is

$\hat I= (-25.0)\hat k +(25.0) \cos 63.4^0 \hati +(25.0) \sin63.4^0 \hatJ\\\\\hat I = (11.2) \hat i + (22.4) \hat j - (23.0) \hat k$

And magnetic field is B = (0.318T)i

Therefore,

$\bar F = \hat I (\bar l \times \bar B)$

$\bar F = (20.0)[(0.112m)i +(0.224m)j-(0.250m)k \times 90.318T)i]$

$= (20.0)(i(0)+j(-0.250)(0.318T)+k[0-(0.224m)(0.318T)]\\\\=(20.0)(-0.250)(0.318)j-(20.0)(0.224)(0.318T)\\\\=-(1.59N)j-(1.425N)k$

Magnitude of the force is

$F = \sqrt{(-1.59N)^2+(-1.425N)^2\\} \\F = 2.135N$

Direction is

$\alpha = \tan^-^1(\frac{-1.425N}{-1.59N} )\\\\= 41.8^0$

Magnitude of the force is 2.135N and the direction is 41.8° below negative y-axis

5 0

3 years ago

Read 2 more answers

a baseball pitcher throws a fastball at 98 mph. he also has a slower "changeup" pitch, 75 mph, which he throws identically, same

notsponge [240]

Answer:

For these reasons at 98 mph the path is straighter

Explanation:

To solve this problem we are going to use the kinematic equations, specifically those of projectile launches, let's calculate the distances that the ball travels

X = Vox t

Y = Yo + Voy t - ½ g t²

They tell us that the only parameter that changes is the speed, so the distance to the plate is known

t = Vox / x

We replace

Y- Yo = Voy (Vox / X) - ½ g (Vox / x)²2

Y -Yo = Vo² sinθ cos θ / x - ½ g Vo² sin²θ / x²

Y -Yo = Vo² (sinθ cosθ / x - ½ g sin²θ / x²)

The trajectory will be flatter when Y is as close as possible to Yo, when examining the right side of the equation, the amount in Parentheses is constant and to what they tell us that the angles and the distance the plate does not change.

Consequently, of the above, the only amount changes is the initial speed if it increases the square of the same increases, so that the height Y approaches the height of the shoulder, that is, DY decreases. For these reasons at 98 mph the path is straighter

7 0

3 years ago

To study the properties of various particles, you can accelerate the particles with electric fields. A positron is a particle wi

Gnom [1K]

Answer:

(a) Acceleration of positron is 6.03 x 10¹³ m/s²

(b) Speed of positron after 8.70 x 10⁻⁹ s is 5.24 x 10⁵ m/s

Explanation:

Given :

Constant electric field, E = 343 N/C

Mass of positron, m = 9.1 x 10⁻³¹ kg

Charge of positron, q = +e = 1.6 x 10⁻¹⁹ C

(a) Coulomb force on the positron is determine by the relation :

F = q x E ....(1)

But, force is also equals to product of mass and acceleration. So,

F = ma .....(2)

Here a is acceleration.

From equation (1) and (2).

m x a = q x E

$a=\frac{qE}{m}$

Substitute the values of q, E and m in the above equation.

$a=\frac{1.6\times10^{-19}\times 343}{9.1\times10^{-31} }$

a = 6.03 x 10¹³ m/s²

(b) Initially, the positron is at rest, so its initial speed is zero.

The equation of motion for positron is :

v = u + at

Here v is final speed, u is initial speed and t is time.

Since, u is zero, so the equation becomes :

v = at

Substitute 8.70 x 10⁻⁹ s for t and 6.03 x 10¹³ m/s² for a in the above equation.

v = 6.03 x 10¹³ x 8.70 x 10⁻⁹ m/s

v = 5.24 x 10⁵ m/s

6 0

3 years ago

What type of cells provide humoral immunity ?

bazaltina [42]

Answer:

Antibody molecules that are secreted by plasma cells mediate the humoral immune response. The antigen that binds to the receptor of the B-cell antigen signals B cells and is internalized and transformed into peptides that activate the armed helper at the same time.

Explanation:

4 0

3 years ago

Read 2 more answers