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noname [10]
1 year ago
6

What is the solution to the following system of equations?

Mathematics
2 answers:
jeyben [28]1 year ago
7 0

Answer:

x = 6 , y= -2

Step-by-step explanation:

=1 ( 2x + 3y =6)

2( x+y=4)

2x+3y =6 (1)

2x+2y = 8 (2)

by eq 1 and 2 using elimination method

y = -2

putting y in eq 2

2x + 2(-2)=8

2x -4 =8

2x =8+4

2x=12

x= 6

liraira [26]1 year ago
6 0

Answer:

x = 6 ,  y = -2

Step-by-step explanation:

2 x + 3 y = 6  (Equation 1)

x + y = 4        (Equation 2)

<u>Solving by substitution</u> :

(Equation 2) ⇒ y = 4 - x

<u>Substitute y by 4 - x in (equation 1)</u> :

2 x + 3 (4 - x) = 6

Then

2 x + 12 - 3x = 6

Then

12 - x = 6

Then

12 - 6 = x

Then

x = 6

<u>We obtain</u> :

y = 4 - x and x = 6

Then

y = 4 - 6

  = -2

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2 years ago
The diagram shows one way to develop the formula for the area of a circle. Pieces of a circle with radius r are rearranged to cr
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