Answer:
The net ionic equation for the reaction between aqueous solutions of hf and koh is H⁺ + OH⁻ → H₂O (l)
Explanation:
This is the complete reaction:
HF (aq)+ KOH (aq) → KF (aq) + H₂O (l)
Hydrofluoric acid dissociates according to this equation:
HF → H⁺ + F⁻
And we get protons plus fluorides.
Sodium hydroxide dissociates into:
KOH → K⁺ + OH⁻
potassium cation and hydroxyls.
First of all, the aqueous compounds must be separated into their ions.
Aqueous are the only one, you can break apart.
Don't forget to establish solubility in the compounds. For this case no one is soluble in water.
We make the complete ionic equation with all the aqueous compounds:
H⁺ + F⁻ + K⁺ + OH⁻ → F⁻ + K⁺
and afterwards, cancel the ions that are repeat on reactant and product sides. This are the spectator ions.
As we eliminate F⁻ + K, the net ionic equation will be:
H⁺ + OH⁻ → H₂O (l)
