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Nuetrik [128]
3 years ago
5

Me need answer to da question ​

Chemistry
1 answer:
Neporo4naja [7]3 years ago
3 0

Answer:

cells?

Explanation:

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When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 2400 k is equal to 1.22×105
rosijanka [135]
When adjusted for any changes in δh and δs with temperature, the standard free energy change δg∘t at 2400 k is equal to 1.22×105j/mol, then the equilibrium constant at 2400 k is 2.21×10−3. The answer to the statement is 2.21×10−3.
6 0
3 years ago
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What is true about the formation of a bond?
timama [110]

Answer:

There is an overall release of energy when bonds form.

Explanation:

There is a general release of energy when bonds form. This energy is called bond energy.

Bond energy is involved in the breakdown or formation of one or more bonds between atoms of a molecule. Atoms bond with each other to achieve their electronic stability, that is, they move from a higher energy situation to a lower energy one. With this we can state that when the bond between atoms is formed, energy is released; therefore, its breakdown depends on energy absorption.

3 0
3 years ago
Write a full chemical equation for the reactions between magnesium and sulfuric acid
melamori03 [73]

Answer:

magnesium + hydrochloric acid → hydrogen gas + magnesium chloride

explanation:

the nitrogen in HNO3 is in the +5 oxidation state and is easily reduced. The reduction would result in the oxidation of the hydrogen gas, forming the water once again.The sulfur in H2SO4 is also in its highest oxidation state, +6.

<em>Hope</em><em> this</em><em> helps</em><em> </em><em>:</em><em>)</em>

6 0
3 years ago
Hydroxylamine is a weak molecular base with kb = 6.6 x 10-9. what is the ph of a 0.0500 m solution of hydroxylamine?
7nadin3 [17]
Answer is: pH of hydroxylamine solution is 9,23.

Kb(NH₂OH) = 1,8·10⁻⁵<span>.
c</span>₀(NH₂OH)<span> = 0,0500 M = 0,05 mol/L.
c(NH</span>₂⁺) = c(OH⁻) = x.

c(NH₂OH<span>) = 0,05 mol/L - x.
Kb = c(NH</span>₂⁺) · c(OH⁻) / c(NH₂OH).

0,0000000066 = x² /  (0,05 mol/L - x). 

solve quadratic equation: x = c(OH⁻) = 0,000018 mol/L.<span>
pOH = -log(</span>0,000018 mol/L) = 4,74.<span>
pH = 14 - 4,74 = 9,23.</span>


4 0
3 years ago
The diagram shows the electron arrangement in a molecule of ammonia, showing only outer
rusak2 [61]

Answer:

Since this is old, im just gonna get these points, don't wan't them to go to waste lm.ao

Explanation:

3 0
3 years ago
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