Answer:
Explanation:
atomic mass
In 1869, Mendeleev published the first periodic table of the elements. In his periodic table, Mendeleev arranged elements in rows by increasing atomic mass. Within a row, elements with lower atomic masses were on the left. Mendeleev started a new row every time the chemical properties of the elements repeated.
Answer:
(R = 8.31 J/(mol · K)) 0.88 × 104 J/mol 1.42 × 102 J/mol 1.42 × 104 J/mol at 600 K and 6.2 × 10-4 L/(mol · s) at 900 K. Calculate the activation energy.
The answers this question is A.
Answer:
Explanation:Calcium oxide (CaO), commonly known as quicklime or burnt lime, is a widely used chemical ... Chemical formula. CaO ... Both it and a chemical derivative (calcium hydroxide, of which quicklime is the base anhydride) are important commodity ... The major use of quicklime is in the basic oxygen steelmaking (BOS) process.
Answer : The density of an object is, 
Solution : Given,
Mass of an object = 60 g
Volume of an object = 
Formula used :

Now put all the given values in this formula, we get the density of an object.

Therefore, the density of an object is, 