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sladkih [1.3K]
3 years ago
6

A company issued 6%, 15-year bonds with a face amount of $67 million. The market yield for bonds of similar risk and maturity is

6%. Interest is paid semiannually. At what price did the bonds sell? (FV of $1, PV of $1, FVA of $1, PVA of $1, FVAD of $1 and PVAD of $1)
Chemistry
1 answer:
mr Goodwill [35]3 years ago
8 0

Answer:

Bond is expected to be sold at the face value .

Explanation

In cases where market interest rate of bond is lower than coupon rate of bond, the bond is issued at a premium. Reason being that company is giving higher  interest rate on bond , this higher rate of interest  increases the price of bond, thus, bond is issued at premium.

In a scenario where market interest rate of bond is higher than coupon rate of bond, the bond is issued at Discount. This is so in that company is not returning more than market rate, therefore, to compensate that, the sale value of bond is usually lower than face value.

If the Market rate and coupon rate is equal , then bond will be issued at face value.

Considering the given question, Coupon rate of bond is 6% and market rate is also 6%. In this question , Market yield is considered to be market rate .

Therefore, there is no need to calculate present value of interest payments and redemption value at maturity to calculate price of bond.

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A 5.325g sample of methyl benzoate, a compound in perfumes , was found to contain 3.758 g of carbon, 0.316 g of hydrogen, and 1.
Alexxandr [17]

<u>Answer:</u> The empirical and molecular formula of the compound is C_4H_4O and C_8H_8O_2 respectively

<u>Explanation:</u>

We are given:

Mass of C = 3.758 g

Mass of H = 0.316 g

Mass of O = 1.251 g

To formulate the empirical formula, we need to follow some steps:

  • <u>Step 1:</u> Converting the given masses into moles.

Moles of Carbon =\frac{\text{Given mass of Carbon}}{\text{Molar mass of Carbon}}=\frac{3.758g}{12g/mole}=0.313moles

Moles of Hydrogen = \frac{\text{Given mass of Hydrogen}}{\text{Molar mass of Hydrogen}}=\frac{0.316g}{1g/mole}=0.316moles

Moles of Oxygen = \frac{\text{Given mass of oxygen}}{\text{Molar mass of oxygen}}=\frac{1.251g}{16g/mole}=0.078moles

  • <u>Step 2:</u> Calculating the mole ratio of the given elements.

For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 0.078 moles.

For Carbon = \frac{0.313}{0.078}=4.01\approx 4

For Hydrogen  = \frac{0.316}{0.078}=4.05\approx 4

For Oxygen  = \frac{0.078}{0.078}=1

  • <u>Step 3:</u> Taking the mole ratio as their subscripts.

The ratio of C : H : O = 4 : 4 : 1

The empirical formula for the given compound is C_4H_4O

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is:

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 130 g/mol

Mass of empirical formula = 68 g/mol

Putting values in above equation, we get:

n=\frac{130g/mol}{68g/mol}=1.9\approx 2

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(2\times 4)}H_{(2\times 4)}O_{(2\times 2)}=C_8H_8O_2

Hence, the empirical and molecular formula of the compound is C_4H_4O and C_8H_8O_2 respectively

4 0
3 years ago
The acid-dissociation constant of hydrocyanic acid (hcn) at 25.0 °c is 4.9 ⋅ 10−10. what is the ph of an aqueous solution of 0.0
vodomira [7]
According to the reaction equation:

and by using ICE table:

              CN-  + H2O ↔ HCN  + OH- 

initial  0.08                        0          0

change -X                        +X          +X

Equ    (0.08-X)                    X            X

so from the equilibrium equation, we can get Ka expression

when Ka = [HCN] [OH-]/[CN-]

when Ka = Kw/Kb

               = (1 x 10^-14) / (4.9 x 10^-10)

               = 2 x 10^-5

So, by substitution:

2 x 10^-5 = X^2 / (0.08 - X)

X= 0.0013

∴ [OH] = X = 0.0013 

∴ POH = -㏒[OH]

            = -㏒0.0013

            = 2.886 

∴ PH = 14 - POH

         = 14 - 2.886 = 11.11
5 0
3 years ago
According to the Law of Conservation of Mass, the total
dimulka [17.4K]

Answer:

Always equal to the total moles of the products.

Explanation:

The law of conservation of mass states that mass in an isolated system is neither created nor destroyed by chemical reactions or physical transformations. According to the law of conservation of mass, the mass of the products in a chemical reaction equal to the mass of the reactants.

8 0
2 years ago
How many carbon atoms are there in 2 molecules of CCI
Anettt [7]

Answer:

Explanation:

No moraculos si a minha memoria não me trai acho temus 2tomos d carbono

4 0
3 years ago
Perform each of the following unit conversions using the conversion factors given below:
andrezito [222]

1. 1086.04 mmHg

2.70.213 mmHg

3. 95.954 kPa

<h3>Further explanation</h3>

Pressure (P) is the force applied per unit area

Can be formulated :

\tt P=\dfrac{F}{A}

P = pressure (SI=Pascal(Pa))

F= force applied (N)

A=area(m²)

The unit of pressure can be expressed in atm, mmHg, or Pascal

\tt 1.\dfrac{1.429}{1}\times 760=1086.04~mmHg

\tt 2)~9,361~Pa=9.361~kPa=\dfrac{9.361}{101.325}\times 760=70.213~mmHg

\tt 3)\dfrac{725}{760}\times 1=0.947~atm=\dfrac{0.947}{1}\times 101.325=95.954~kPa

4 0
2 years ago
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