H2SO4 + 2NH4OH → (NH4)2SO4 + 2HOH Which of these would be the BEST description of this reaction? A) reduction B) combustion C) n
2 answers:
Answer: C) neutralization
Explanation:
A. Reduction is a type of chemical reaction in which substance is made to gain electrons or gain hydrogen.
Example:
B. Combustion is a type of chemical reaction in which fuel is reacted with oxygen to form carbon dioxide and water.
Example:
C. Neutralization reaction is defined as the chemical reaction in which an acid reacts with a base to produce a salt and water molecule.
D. Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.
Example:
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Answer : Option (A) Accelerator 2 model has the lowest percentage of energy lost as waste.
Solution : Given,
For Accelerator 1 model,
Input energy = 2078.3 J
Wasted energy = 663.1 J
Output energy = 1415.2 J
For Accelerator 2 model,
Input energy = 7690.0 J
Wasted energy = 2337.5 J
Output energy = 5353.5 J
For Accelerator 3 model,
Input energy = 4061.9 J
Wasted energy = 2259.6 J
Output energy = 1802.3 J
Formula used for lowest percentage of energy lost as waste is:
% energy lost as waste = (Total energy wasted / Total input energy ) × 100
For Accelerator 1 model,
% energy lost as waste = = 31.90%
For Accelerator 2 model,
% energy lost as waste = = 30.39%
For Accelerator 3 model,
% energy lost as waste = = 55.62%
So, we conclude that the Accelerator 2 model has the lowest percentage of energy lost as waste.
Answer:
At equilibrium, the concentration of is going to be 0.30M
Explanation:
We first need the reaction.
With the information given we can assume that is:
+
⇄ 2
If there is placed 0.600 moles of NO in a 1.0-L vessel, we have a initial concentration of 0.60 M NO; and no nor
present. Immediately,
and
are going to be produced until equilibrium is reached.
By the ICE (initial, change, equilibrium) analysis:
I: []=0 ; [
]= 0 ; [
]=0.60M
C: []=+x ; [
]= +x ; [
]=-2x
E: []=0+x ; [
]= 0+x ; [
]=0.60-2x
Now we can use the constant information:
=
=
=
At equilibrium, the concentration of is going to be 0.30M