Question

In state n = 1, the energy of the hydrogen atom is -13.58 ev. what is its energy in state n = 2?

Answer 1

The energy of a hydrogen atom in energy level n = 2 is 3.4 eV.

The ionization of energy of the hydrogen atom is 13.6 eV.

This is the minimum energy required to raise the electron from its ground state in the hydrogen atom.

n represents the Energy level.

When an electron changes from one energy level to another, the energy of the atom must change as well.  It requires energy to promote an electron from a lower energy level to a higher one.  This energy can be supplied by a photon whose energy E is given in terms of its frequency E = hf or wavelength E = hc/λ.

The formula for the energy of an atom is:

E = 13.6 * $Z^{2}$ / $n^{2}$  .... this represents the allowed energy level in the hydrogen       atom

  = 13.6 * 1 / $2^{2}$    since Z = 1 for hydrogen where Z is mass of atom

  = 13.6 / 4

  = 3.4 eV

The energy of a hydrogen atom in energy level n = 2 is 3.4 eV.

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