The energy of a hydrogen atom in energy level n = 2 is 3.4 eV.
The ionization of energy of the hydrogen atom is 13.6 eV.
This is the minimum energy required to raise the electron from its ground state in the hydrogen atom.
n represents the Energy level.
When an electron changes from one energy level to another, the energy of the atom must change as well. It requires energy to promote an electron from a lower energy level to a higher one. This energy can be supplied by a photon whose energy E is given in terms of its frequency E = hf or wavelength E = hc/λ.
The formula for the energy of an atom is:
E = 13.6 * /
.... this represents the allowed energy level in the hydrogen atom
= 13.6 * 1 / since Z = 1 for hydrogen where Z is mass of atom
= 13.6 / 4
= 3.4 eV
The energy of a hydrogen atom in energy level n = 2 is 3.4 eV.
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# SPJ4
739 is the number of atoms of O in 92.3 moles of Cr3(PO4)2.
Explanation:
Molecular formula given is = Cr3(PO4)2
number of moles of the compound is 92.3 moles
number of 0 atoms in 92.3 moles =?
From the chemical formula 1 mole of the compound has 8 atoms of oxygen
So, it can be written as
1 mole Cr3(PO4)2 has 8 atoms of oxygen
92.3 moles of Cr3(PO4)2 has x atoms of oxygen
=
x = 8 x 92.3
x = 738.4 atoms
There will be 739 oxygen atoms in the 92.3 moles of Cr3(PO4)2.