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GREYUIT [131]
3 years ago
13

Identify the following as an example of a physical property or a chemical property. A bar of lead is more easily bent (malleable

) than a bar of aluminum of the same size.
Chemistry
2 answers:
Nastasia [14]3 years ago
7 0
This is a physical property, because chemical properties change the composition of the substances but in this case that doesn't happen. It only changes the shape of the lead.
weqwewe [10]3 years ago
5 0

Explanation:

Physical property is the property which can be measured.

For example, density, weight, mass, malleability, ductility etc are all physical properties.

Whereas a property that brings chemical changes in a substance is known as chemical property.

For example, reactivity, toxicity etc are all chemical properties.

Hence, when a bar of lead is more easily bent (malleable) than a bar of aluminum of the same size then it depicts physical property as no new bonds have been formed.

Thus, we can conclude that given example is an example of physical property.

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jok3333 [9.3K]

Answer:

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Explanation:

5 0
3 years ago
Bicarbonate concentrate mixers may have a which are replaced on a routine basic.
Sidana [21]

Answer: True the bicarbonate mixture can help save time and few routine.

Explanation:

For the purpose of making dialysate for hemodialysis patient therapies a bicarbonate mixing and delivering systems designed to prepare a liquid sodium bicarbonate formulation comes in handy.

Certain systems like the SDS unit also allow for the transfer and distribution of acid concentrate solutions. We also provide stand-alone acid concentrate delivery systems using a variety of holding tanks and delivery methods. 

A challenge for hemodialysis providers is to properly provide bicarbonate solution in a cost effective manner. Preparation and disinfection can be time-consuming and labor intensive.

Bicarbonate however can corrode certain metals and painted surfaces leaving your preparation area encrusted and grimy.

Furthermore, if not mixed properly, bicarbonate can negatively affect the dialysate solution.

The answer to the above is true the bicarbonate mixture can help save time and few routine.

3 0
4 years ago
What is the displacement of the particle in the time interval 7 seconds to 8 seconds?
3241004551 [841]

Answer:

28 is great.......... it should be snSwer

8 0
3 years ago
A sample of an ideal gas in a cylinder of volume 2.67 L at 298 K and 2.81 atm expands to 8.34 L by two different pathways. Path
Igoryamba

Explanation:

  • For path A, the calculation will be as follows.

As, for reversible isothermal expansion the formula is as follows.

            W = -2.303 nRT log(\frac{V_2}{V_1})

Since, we are not given the number of moles here. Therefore, we assume the number of moles, n = 1 mol.

As the given data is as follows.

              R = 8.314 J/(K mol),          T = 298 K ,

          V_{2} = 8.34 L,    V_{1} = 2.67 L

Now, putting the given values into the above formula as follows.

            W = -2.303 nRT log(\frac{V_2}{V_1})

   = -2.303 \times 1 \times 8.314 J/K mol \times 298 log(\frac{8.34}{2.67})

     = -2.303 \times 1 \times 8.314 J/K mol \times 298 \times 0.494

    = -2818.68 J

Hence, work for path A is -2818.68 J.

  • For path B, the calculation will be as follows.

Step 1: When there is no change in volume then W = 0

Hence, for step 1, W = 0

Step 2: As, the gas is allowed to expand against constant external pressure P_{external} = 1.00 atm.

So,              W = -P_{external} \times \Delta V

Now, putting the given values into the above formula as follows.

               W = -P_{external} \times \Delta V

                   = -1 atm \times (8.34 L - 2.67 L)  

                    = -5.67 atm L

As we known that, 1 atm L = 101.33 J

Hence, work will be calculated as follows.

       W = -\frac{101.33 J}{1 atm L} \times 5.67 atm L

            = -574.54 J

Therefore, total work done by path B = 0 + (-574.54 J)

                        W = -574.54 J

Hence, work for path B is -574.54 J.

3 0
4 years ago
Which orbitals from a pi bond?
QveST [7]

Answer:

B. The s orbital and two p orbitals

Explanation:

8 0
3 years ago
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