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N76 [4]
3 years ago
11

Which descriptions apply to emitted radiation? check all that apply?

Chemistry
1 answer:
Murrr4er [49]3 years ago
7 0
<span>measurement in Ci/Bq

the amount of radioactive materials released into the environment.

number of disintegrations of radioactive atoms in a radioactive material over a period of time</span>
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EZ POINTS HELP PLEASE
Dima020 [189]

Answer:

I`m pretty sure that B is right

Explanation:

7 0
3 years ago
What Element is among the five most abundant element in the sun earth ocean atmosphere and organisms?
larisa86 [58]

Answer:

i would have to say oxygen .

Explanation:

6 0
3 years ago
How many atoms of oxygen are present: 3Al2(SO4)3<br> a. 36<br> b. 12<br> c. 10<br> d. 24
Ira Lisetskai [31]

Answer:

the answer is 12

Explanation:

In one formula unit of Al2(SO4)3 A l 2 ( S O 4 ) 3 , there would be twelve atoms of oxygen.

6 0
2 years ago
Explain how atomic
snow_lady [41]

Answer:A higher effective nuclear charge causes greater attractions to the electrons, pulling the electron cloud closer to the nucleus which results in a smaller atomic radius. Down a group, the number of energy levels (n) increases, so there is a greater distance between the nucleus and the outermost orbital.

5 0
3 years ago
Read 2 more answers
Which ion does not have a noble gas configuration in its ground state? which ion does not have a noble gas configuration in its
Luda [366]

Answer: Option (d) is the correct answer.

Explanation:

The atomic number of Al is 13, so the electronic configuration of Al is as follows.

            1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}

         = [Ne]3s^{2}3p^{1}

Al^{3+} = [Ne]

The atomic number of Sc is 21, so the electronic configuration of Sc is as follows.

         1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{1}

        = [Ar]4s^{2}3d^{1}

 Sc^{3+} = [Ar]

The atomic number of As is 33, so the electronic configuration of As is as follows.

         1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{3}

         = [Ar]4s^{2}3d^{10}4p^{3}

 As^{3-} = [Ar]4s^{2}3d^{10}4p^{6} = [Kr]

The atomic number of Ga is 31, so the electronic configuration of Ga is as follows.

        1s^{2}2s^{2}2p^{6}3s^{2}3p^{6}4s^{2}3d^{10}4p^{1}

       = [Ar]4s^{2}3d^{10}4p^{1}

 Ga^{3+} = [Ar]3d^{10}

Therefore, we can conclude that galium (Ga) ion does not have a noble gas configuration in its ground state.

4 0
3 years ago
Read 2 more answers
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