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N76 [4]
3 years ago
11

Which descriptions apply to emitted radiation? check all that apply?

Chemistry
1 answer:
Murrr4er [49]3 years ago
7 0
<span>measurement in Ci/Bq

the amount of radioactive materials released into the environment.

number of disintegrations of radioactive atoms in a radioactive material over a period of time</span>
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What does a student need to know about double bonds and triple bonds when predicting molecular geometry of molecules?
zhuklara [117]

This problem is asking for an explanation of what we need to know about double and triple bonds to successfully predict molecular geometries in molecules. At the end, one comes to the conclusion that double and triple bonds contribute to the degree in which an atom is bonded and they also determine the lone pairs, which, at the same time,  define the molecular geometry.

<h3>Molecular geometry:</h3>

In chemistry, molecules are not necessarily flat arrangements of atoms, yet they have specific bond angles, orientations and shapes, which define the molecular geometry. In such a way, we can use the VSEPR theory in order to know the molecular geometry of a molecule; however, we first need its Lewis structure or at least the number and type of bonds to do so.

Consider water and carbon dioxide; the former has two hydrogen to oxygen bonds (O-H) and 2 lone pairs because O has six valence electrons but just 2 are bonded to complete the octet, so 4 unpaired electrons lead to two lone pairs. On the other hand, the latter has two double bonds (C=O) and 0 lone pairs because carbon has four valence electrons and they are all bonded to complete the octet.

In such a way, one can see how the double bond affected the bonding in CO2 in contrast to the H2O; situation that also applies to triple bonds, because CO2 has a linear molecular geometry whereas water has a bent one (see attached picture)

Hence, one comes to the conclusion that double and triple bonds contribute to the degree in which an atom is bonded and they also determine the lone pairs, which, at the same time, define the molecular geometry.

Learn more about molecular geometry: brainly.com/question/7558603

Learn more about the VSEPR theory:  brainly.com/question/14225705

5 0
2 years ago
How many total orbitals are within the 3s, 3p, and<br> energy level?
Nina [5.8K]

The answer for the following question is explained below.

Therefore the total number of orbitals are " 9 ".

Explanation:

Orbital:

An orbital is a mathematical function that describes the wave-like behavior of an electron,electron pair,or the nucleons.

The total number of orbitals present in the 3rd energy level is 9.

Here,

A 3 s subshell has only one orbital.

A 3 p subshell has three orbitals.

A 3 d subshell has five orbitals.

Therefore the total number of orbitals is:

3 s = 1 orbital

3 p = 3 orbitals

3 d = 5 orbitals

total orbitals in 3rd energy level is = 1 + 3 + 5 =9

Therefore the total number of orbitals are " 9 ".

7 0
3 years ago
Read 2 more answers
Determine the class of the compound, which contains carbon, hydrogen, and oxygen, and exhibits the infrared spectrum below. poss
Talja [164]
I have attached an image of the IR spectrum required to answer this question.

Looking at the IR, we can look for any clear major stretches that stand out. Immediately, looking at the spectrum, we see an intense stretch at around 1700 cm⁻¹. A stretch at this frequency is due to the C=O stretch of a carbonyl. Therefore, we know our answer must contain a carbonyl, so it could still be a ketone, aldehyde, carboxylic, ester, acid chloride or amide. However, if we look in the 3000 range of the spectrum, we see some unique pair of peaks at 2900 and 2700. These two peaks are characteristic of the sp² C-H stretch of the aldehyde.

Therefore, we can already conclude that this spectrum is due to an aldehyde based on the carbonyl stretch and the accompanying sp² C-H stretch.

8 0
3 years ago
Balance the equation with the correct coefficients.
Dmitry [639]

Explanation:

In general, to balance an equation, here are the things we need to do:

Count the atoms of each element in the reactants and the products.

Use coefficients; place them in front of the compounds as needed.

7 0
2 years ago
The results of the gold foil experiment led to the conclusion that an atom is
viva [34]

\sf\large \blue{\underbrace{\red{Answer⋆}}}:

The nucleus of an atom of the element is positively charged and atom has a hollow space inside it.

Explanation:

This experiment was conducted by Rutherford in this experiment. He placed a gold foil and surround it with a screen.

And He exposed gold foil in alpha particles rays in which he noticed that most rays passed through atom which conclude that atom has a large space, some rays get deflected and some reverse their path this show that the positive charge of nucleus of an atom.

4 0
2 years ago
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