Question

Determine the number of atoms of O in 92.3 moles of Cr3(PO4)2

Answer 1

739 is the number of atoms of O in 92.3 moles of Cr3(PO4)2.

Explanation:

Molecular formula given is  = Cr3(PO4)2

number of moles of the compound is 92.3 moles

number of 0 atoms in 92.3 moles =?

From the chemical formula 1 mole of the compound has 8 atoms of oxygen

So, it can be written as

1 mole Cr3(PO4)2 has 8 atoms of oxygen

92.3 moles of Cr3(PO4)2 has x atoms of oxygen

$\frac{8}{1}$ = $\frac{x}{92.3}$

x = 8 x 92.3

x = 738.4 atoms

There will be 739 oxygen atoms in the 92.3 moles of Cr3(PO4)2.