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qaws [65]
2 years ago
9

The following reaction can be used to make H₂ for the synthesis of ammonia from the greenhouse gases carbon dioxide and methane:

CH₄(g) + CO₂(g) ⇄ 2CO)g) + 2H₂(g)(b) What is the percent yield of H₂ for this system at 1300. K, at which Kp = 2.626x10⁷ ?
Chemistry
1 answer:
olchik [2.2K]2 years ago
3 0

The artificial fixation of nitrogen (N2) has enormous energy, environmental, and societal impact, the most important of which is the synthesis of ammonia (NH3) for fertilizers that help support nearly half of the world's population.

<h3>Artificial fixation of nitrogen</h3>

We can generate ammonia gas in the research centre by slowly heating ammonium chloride (NH4Cl) and slaked lime [Ca(OH)2].

The following reaction can be used to make H₂ for the synthesis of ammonia from the greenhouse gases carbon dioxide and methane: CH₄(g) + CO₂(g) ⇄ 2CO)g) + 2H₂(g

When added to a solution of copper sulfate, ammonia turns the solution deep blue.

NH3 + CuSO4 + nH2O→ [Cu(NH3)4(H2O)n]SO4

To learn more about Artificial fixation visit the link

brainly.com/question/8951119

#SPJ4

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At a certain temperature this reaction follows first-order kinetics with a rate constant of 0.184 s^-1 ? Suppose a vessel contai
meriva

Answer:

0.57 M

Explanation:

rate = change in concentration /time

Initial concentration of Cl2O5 = 1.16 M

Let the concentration of Cl2O5 after 5.70 seconds be y

rate = (1.16 - y)/5.7

The reaction follows a first order

Therefore, rate = ky = 0.184y

0.184y = (1.16 - y)/5.7

0.184y × 5.7 = 1.16 - y

1.0488y + y = 1.16

2.0488y = 1.16

y = 1.16/2.0488 = 0.57 M

Concentration of Cl2O5 after 5.70 seconds is 0.57 M

6 0
4 years ago
Please help with #2 and #3
Vaselesa [24]

Answer:

2. V_2=17L

3. V=82.9L

Explanation:

Hello there!

2. In this case, we can evidence the problem by which volume and temperature are involved, so the Charles' law is applied to:

\frac{V_2}{T_2}=\frac{V_1}{T_1}

Thus, considering the temperatures in kelvins and solving for the final volume, V2, we obtain:

V_2=\frac{V_1T_2}{T_1}

Therefore, we plug in the given data to obtain:

V_2=\frac{18.2L(22+273)K}{(45+273)K} \\\\V_2=17L

3. In this case, it is possible to realize that the 3.7 moles of neon gas are at 273 K and 1 atm according to the STP conditions; in such a way, considering the ideal gas law (PV=nRT), we can solve for the volume as shown below:

V=\frac{nRT}{P}

Therefore, we plug in the data to obtain:

V=\frac{3.7mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=82.9L

Best regards!

6 0
3 years ago
What is equal to the number of particles in 36 grams of carbon-12?
HACTEHA [7]

Answer:

3 moles

Explanation:

To solve this problem we will  use the Avogadro numbers.

The number 6.022×10²³ is called Avogadro number and it is the number of atoms, ions or molecules in one mole of substance.  According to this,

1.008 g of hydrogen = 1 mole =  6.022×10²³  atoms.

18 g water = 1 mole = 6.022×10²³ molecules

we are given 36 g of C-12. So,

12 g of C-12 = 1 mole

24 g of C-12 =  2 mole

36 g of C-12 = 3 mole

So 3 moles of C-12 equals to the number of particles in 36 g of C-12.

4 0
3 years ago
2. Carbon-11 is a radioactive isotope of carbon. Its half-life is 10 minutes.
Annette [7]
It’s probably probably 01/16 because of the other number don’t make sense except that one
5 0
3 years ago
Explain how to use an acid-base indicator to determine pH
Annette [7]
Acid-base indicator changes color based on pH.

drop some in a solution n watch the color changes. different indicators show different colors at different pH. they usually have standard colors for comparison.
7 0
3 years ago
Read 2 more answers
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