Answer:
Yes. Since they have more than the required reactants.
Explanation:
Zinc reduces silver nitrate to silver metal according to the following equation.
2AgNO₃ + Zn → 2Ag + Zn(NO₃)₂
From the equation 2 moles of AgNO₃ produce 2 moles of silver.
If we consider the zinc to be used number of moles=mass/RAM
RAM of zinc =65.38
No. of moles=500/65.38
=7.6476moles
To produce 800 grams of silver they require:
800/107.868 moles=7.4165 moles of silver nitrate since the ratio of silver nitrate to silver produced is 1:1
The number of moles of silver nitrate available=1500/169.872
=8.83 moles.
As the amount of reactants available is more than the required the company will make it in producing the 800 grams of silver required.
Answer:
The answer is option C
Explanation:
To calculate the mass of oxygen gas we must first find the number of moles of sulphur
Molar mass = number of moles (n) / mass
n = mass / Molar mass
From the question
Molar mass (M) of Sulphur = 32g/mol
mass = 56g
n( Sulphur) = 56/32 = 1.75mol
Since the moles of oxygen and sulphur are the same
M(O2) = 16 × 2 = 32g/mol
Mass of oxygen = molar mass × moles
= 32 × 1.75
<h3>= 56g</h3>
Hope this helps you
Answer:
d. forced migration
Explanation:
Certain hazardous occurrences affect living organisms in their natural habitat. One of those occurrences is forest fire. Forest fire or vegetation fire is an uncontrollable break out of fire in a vegetation, affecting the inhabitants of the area.
The occurrence of a forest fire will lead to a forced migration of organisms from their natural habitat. Animals and other mobile organisms will be forced to leave behind their devastating habitat and migrate to a less threatened area in order to survive.
Dobereiner's triads were an early attempt to sort the elements into some logical order by their physical properties. The appearance and reactions of the elements in a triad were similar to each other. He showed that in each triad the mean of the lightest and heaviest atomic weights approximated the atomic weight of the middle element.
Hi sorry
I don’t know
but maybe next time
