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Lina20 [59]
2 years ago
12

Using bond lengths in Table 9.2 (p. 371) and assuming ideal geometry, calculate each of the following distances:

Chemistry
1 answer:
Fed [463]2 years ago
7 0

<u>158 pm</u> is the distance Between equatorial Fluorine atoms in PF₅<u>(</u>Phosphorus pentafluoride).

<h3>What is Fluorine?</h3>

The chemical element fluorine has an atomic number of 9 and the symbol F. The lightest halogen, it is an extremely poisonous, pale yellow diatomic gas under normal conditions. It is exceedingly reactive and, as the most electronegative element, reacts with all other elements with the exception of argon, neon, and helium.

Fluorine is the 24th most abundant element overall and the 13th most abundant on Earth. In order to decrease the melting temperatures of metal ores for smelting, fluorite, the main mineral source of fluorine, was added. The Latin verb fluo, which means "flow," gave the mineral its name. Fluorite was first described in 1529.

Learn more about fluorine

brainly.com/question/24373411

#SPJ4

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Procaine hydrochloride (MW = 273) is a 2-ion electrolyte, dissociating 80%. Calculate its dissociation factor. Round to tenths p
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Answer:

Dissociation factor = 1.8

Explanation:

Data provided in the question:

Molecular weight of the Procaine hydrochloride = 273

Number of ions contained, n = 2

Fraction Dissociating, α = 80% = 0.8

Now,

the  dissociation factor 'i' is given as:

i = 1 + α × ( n - 1 )

on substituting the respective values, we get

i = 1 + 0.8 × ( 2 - 1 )

or

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or

i = 1.8

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