Question

What is the total number of atoms contained in 2.11 moles of nickel?

Answer 1

  The  total  number of atoms  contained  in 2.11  moles  of nickel is
1.27 x10^24 atoms

            calculation

By  use of Avogadro  law constant

 That is   1 mole= 6.02 x10^23  atoms
what  about  2.11  moles of nickel

  by  use of cross  multiplication
[ 2.11  moles  x ( 6.02 x10^23)] / 1 moles = 1.27 x10^24 atoms

Answer 2

1.27 × 10²⁴ atoms of nickel are contained in 2.11 moles of nickel. For every mole of a substance there are 6.022 × 10²³ representative particles of that substance. The amount of particles in one mole of substance is called Avogadro's number.

Further Explanation

To convert from the number of moles to number of representative particles, the formula below may be used:

$\boxed {no. \ of \ particles \ = given \ no. \ of \ moles \times \frac{6.022 \times 10^{23} \ particles}{1 \ mole}}$

For this problem, the number of nickel atoms can be determined by plugging in the given values in the equation above:

$no. \ of \ Ni \ atoms = 2.11 \ mol \ Ni \times \frac{6.022 \times 10^{23} Ni \ atoms}{1 \ mol \ Ni}\\\\\boxed {no. \ of \ Ni \ atoms = 1.270642 \times 10^{24} \ atoms}$

Since the given only has three significant figures, the final answer with the correct number of significant figures is:

$\boxed {\boxed {no. \ of \ Ni \ atoms = 1.27 \times 10^{24} \ atoms}}$

Learn More

1. Learn more about representative particles brainly.com/question/8969313
2. Learn more about Avogadro's number brainly.com/question/229300
3. Learn more about mole conversions brainly.com/question/1370888

Keywords: moles conversion, Avogadro's number