Question

The lesser of two consecutive even integers is 10 more than one-half the greater.Find the integers

Answer 1

The two consecutive integers are 21 and 22.

How to find the two consecutive integers?

Two consecutive integer numbers can be written as x and x + 1.

The lesser of these two numbers is x, and we know that it is 10 more than one-half of the greater integer, then we can write:

x = 10 + (x + 1)/2

Now we can solve that equation for x:

x = 10 + (x + 1)/2

2x = 20 + (x + 1)

2x = 21 + x

x = 21

Then the lesser number is x = 21 and the larger number is x + 1 = 22

If you want to learn more about integer numbers:

brainly.com/question/2493629

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