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1 year ago

In Part Two, you will apply the engineering design process to design your own skate park ramp.

Chemistry

2 answers:

grandymaker [24]1 year ago

7 0

Answer: The constraints could be lack of materials, funds, or time. Another constraint could be size or shape.

Explanation:

E :)

NNADVOKAT [17]1 year ago

7 0

I got 100 for righting E so that’s the answer

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Explain why the nucleus of an atom has a positive electrical charge.

xxTIMURxx [149]

Answer: Nucleus of an atom is heavy and positively charged because nucleus is only made up of protons and neutrons.

6 0

3 years ago

Someone please help me , number 14

MrRa [10]

We know,

PV=nRT
203*20= n*0.0821*373
n=132.5 moles.

6 0

3 years ago

Animals breathe oxygen and release carbon dioxide during cellular respiration according to the equation below. How much oxygen i

kifflom [539]

Answer:

14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.

Explanation:

Animals take in oxygen and breathe out carbon dioxide during cellular respiration. The reaction for the metabolism of the food in the animal body is:

$C_6H_{12}O_6 + O_2 \rightarrow 6CO_2 + 6H_2O + Energy$

As can be seen from the reaction stoichiometry that:

6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.

Also,

Given :

Mass of carbon dioxide gas = 120 g

Molar mass of carbon dioxide gas = 44 g/mol

The formula for the calculation of moles is shown below:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus, moles of carbon dioxide are:

$moles_{CO_2} = \frac{120 g}{44 g/mol}$

$moles_{CO_2} = 2.7273 mol$

As mentioned:

6 moles of carbon dioxide gas can be produced from 1 mole of oxygen gas in the process of metabolism of glucose.

1 mole of carbon dioxide gas can be produced from 1/6 mole of oxygen gas in the process of metabolism of glucose.

2.7273 mole of carbon dioxide gas can be produced from $\frac{1}{6} \times 2.7273$ moles of oxygen gas in the process of metabolism of glucose.

Thus, moles of oxygen gas needed = 0.4545 moles

Molar mass of oxygen gas = 32 g/mol

The mass of oxygen gas can be find out by using mole formula as:

$moles = \frac{Mass\ taken}{Molar\ mass}$

Thus,

$Mass\ of\ oxygen\ gas = Moles \times Molar mass}$

$Mass\ of\ oxygen\ gas = 0.4545 \times 32}$

$Mass\ of\ oxygen\ gas = 14.544 g$

14.544 g of oxygen is needed to produce 120 grams of carbon dioxide.

3 0

3 years ago

Read 2 more answers

I need help with this ASAP PLEASE

Artemon [7]

439.3 g CO2

Explanation:

First find the # of moles of CO2 that results from the combustion of 3.327 mol C3H6:

3.227 mol C3H6 × (6 mol CO2/2 mol C3H6)

= 9.981 mol CO2

Use the molar mass of CO2 to determine the # of grams of CO2:

9.981 mol CO2 x (44.01 g CO2/1 mol CO2)

= 439.3 g CO2

5 0

2 years ago

HClO3 + NH3 Right arrow. NH4+ + ClO3– Which is a base-conjugate acid pair?

romanna [79]

Answer:

NH3 and NH4+

Explanation:

5 0

2 years ago