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2 years ago

In Part Two, you will apply the engineering design process to design your own skate park ramp.

Chemistry

2 answers:

grandymaker [24]2 years ago

7 0

Answer: The constraints could be lack of materials, funds, or time. Another constraint could be size or shape.

Explanation:

E :)

NNADVOKAT [17]2 years ago

7 0

I got 100 for righting E so that’s the answer

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How will increasing the pressure on the system affect this equilibrium reaction?

eduard

No effect because pressure only affects equilibrium in gas state reactions
Hehjsjshhshshshsh

3 0

3 years ago

How much energy is released by the decay of 3 grams of 20Th in the following reaction 230 Th - 226Ra + 'He (230 Th = 229.9837 g/

wolverine [178]

Answer : The energy released by the decay of 3 grams of 'Th' is $2.728\times 10^{-15}J$

Explanation :

First we have to calculate the mass defect $(\Delta m)$ .

The balanced reaction is,

$^{230}Th\rightarrow ^{226}Ra+^{4}He$

Mass defect = Sum of mass of product - sum of mass of reactants

$\Delta m=(\text{Mass of Ra}+\text{Mass of He})-(\text{Mass of Th})$

$\Delta m=(225.9771+4.008)-(229.9837)=1.4\times 10^{-3}amu=2.324\times 10^{-30}kg$

conversion used : $(1amu=1.66\times 10^{-27}kg)$

Now we have to calculate the energy released.

$Energy=\Delta m\times (c)^2$

$Energy=(2.324\times 10^{-30}kg)\times (3\times 10^8m/s)^2$

$Energy=2.0916\times 10^{-13}J$

The energy released is $2.0916\times 10^{-13}J$

Now we have to calculate the energy released by the decay of 3 grams of 'Th'.

As, 230 grams of Th release energy = $2.0916\times 10^{-13}J$

So, 3 grams of Th release energy = $\frac{3}{230}\times 2.0916\times 10^{-13}J=2.728\times 10^{-15}J$

Therefore, the energy released by the decay of 3 grams of 'Th' is $2.728\times 10^{-15}J$

5 0

4 years ago

If a stack of 1,008 alkali fuel cells in series generates 14,800 W of power, and each cell contributes equally to the power of t

USPshnik [31]

Answer:

Each cell contributes power of 14.7 Watts.

Explanation:

Total power generated by alkali furl cells = 14,800 Watts

Total number of fuel cells = 1,008

Power produced by one fuel cell = x

Total power generated = $14,800 Watts=x\times 1,008$

$x=\frac{14,800 Watts}{1,008}=14.6825 Watts\approx 14.7 Watts$

Each cell contributes power of 14.7 Watts.

6 0

3 years ago

Read 2 more answers

A base produces OH-1 ions when dissolved in solution<br> . True<br> . False

lisov135 [29]

Answer:

i think its true

Explanation:

4 0

3 years ago

Let us assume that cu(oh)2(s) is completely insoluble, which signifies that the precipitation reaction with naoh(aq) (presented

yKpoI14uk [10]

<span>Answer: (0.150 L) x (0.0240 M Fe{3+}) x (3 mol OH{-} / 1 mol Fe{3+}) / (1.39 M NaOH) = 0.00777 L = 7.77 mL NaOH</span>

6 0

4 years ago