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emmainna [20.7K]
3 years ago
13

A chemical reaction is occurring inside a beaker and the temperature of the beaker is monitored. What would the contents of the

beaker be referred to as? the system the surroundings the boundary the universe

Chemistry
1 answer:
Archy [21]3 years ago
3 0

<u>Answer:</u>

<em>The system is the Answer </em>

<em></em>

<u>Explanation:</u>

System is the region which is taken into consideration.

While we perform a chemical reaction the system is the substance taken in the container.

So, A thermodynamic system is the amount of matter or the region in universe which is under the study.

The region outside the beaker are called as surroundings.

The beaker (the surface which separates the system from its surroundings) is said to be the boundary

System + surroundings = universe

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Help out please?????
Alexxandr [17]

Answer:

A non- metal

Explanation:

Hope u got ur answer

5 0
3 years ago
Read 2 more answers
If the concentration of Mg2+ in the solution were 0.039 M, what minimum [OH−] triggers precipitation of the Mg2+ ion? (Ksp=2.06×
Elodia [21]

Answer:

2.30 × 10⁻⁶ M

Explanation:

Step 1: Given data

Concentration of Mg²⁺ ([Mg²⁺]): 0.039 M

Solubility product constant of Mg(OH)₂ (Ksp): 2.06 × 10⁻¹³

Step 2: Write the reaction for the solution of Mg(OH)₂

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

Step 3: Calculate the minimum [OH⁻] required to trigger the precipitation of Mg²⁺ as Mg(OH)₂

We will use the following expression.

Ksp = 2.06 × 10⁻¹³ = [Mg²⁺] × [OH⁻]²

[OH⁻] = 2.30 × 10⁻⁶ M

3 0
3 years ago
Suppose of copper(II) acetate is dissolved in of a aqueous solution of sodium chromate. Calculate the final molarity of acetate
uranmaximum [27]

Answer:

0.0714 M for the given variables

Explanation:

The question is missing some data, but one of the original questions regarding this problem provides the following data:

Mass of copper(II) acetate: m_{(AcO)_2Cu} = 0.972 g

Volume of the sodium chromate solution: V_{Na_2CrO_4} = 150.0 mL

Molarity of the sodium chromate solution: c_{Na_2CrO_4} = 0.0400 M

Now, when copper(II) acetate reacts with sodium chromate, an insoluble copper(II) chromate is formed:

(CH_3COO)_2Cu (aq) + Na_2CrO_4 (aq)\rightarrow 2 CH_3COONa (aq) + CuCrO_4 (s)

Find moles of each reactant. or copper(II) acetate, divide its mass by the molar mass:

n_{(AcO)_2Cu} = \frac{0.972 g}{181.63 g/mol} = 0.0053515 mol

Moles of the sodium chromate solution would be found by multiplying its volume by molarity:

n_{Na_2CrO_4} = 0.0400 M\cdot 0.1500 L = 0.00600 mol

Find the limiting reactant. Notice that stoichiometry of this reaction is 1 : 1, so we can compare moles directly. Moles of copper(II) acetate are lower than moles of sodium chromate, so copper(II) acetate is our limiting reactant.

Write the net ionic equation for this reaction:

Cu^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow CuCrO_4 (s)

Notice that acetate is the ion spectator. This means it doesn't react, its moles throughout reaction stay the same. We started with:

n_{(AcO)_2Cu} = 0.0053515 mol

According to stoichiometry, 1 unit of copper(II) acetate has 2 units of acetate, so moles of acetate are equal to:

n_{AcO^-} = 2\cdot 0.0053515 mol = 0.010703 mol

The total volume of this solution doesn't change, so dividing moles of acetate by this volume will yield the molarity of acetate:

c_{AcO^-} = \frac{0.010703 mol}{0.1500 L} = 0.0714 M

8 0
3 years ago
What is the most likely formula for an oxide formed between group a 1 atom x and oxygen
Marizza181 [45]
The most likely formula for an oxide formed between group 1a atom X and oxygen would be

X2O. - X is group 1a atom.
5 0
3 years ago
A sample of sandstone consists of only silica (SiO2) and calcite (CaCO3). When sandstone is heated, calcium carbonate decomposes
anzhelika [568]

Answer:

0

Explanation:

To calculate, the mass of Carbondioxide is 3.45mg

Then the decomposition of Carbondioxide gives 0 on calculation

5 0
3 years ago
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