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oee [108]
4 years ago
13

Write the balanced nuclear equation for β− decay of silicon−32. Include both the mass numbers and the atomic numbers with each n

uclear symbol. Use the "sup-subscript" button in the answer palette to enter these numbers correctly. Greek letters can be accessed in the drop-down menu that says "Main Keypad."
Chemistry
1 answer:
weqwewe [10]4 years ago
8 0

Answer:

^{32}_{14}Si\rightarrow ^{32}_{15}P+e^-+\bar{v}_e

Explanation:

Beta decay conserves the lepton number. In \beta^- decay, the atomic number of the element increases which is accompanied by the release of  an electron antineutrino, e^-+\bar{v}_e.

For example:-

^A_ZX\rightarrow ^A_{Z+1}X+e^-+\bar{v}_e

The \beta^- decay of silicon-32 is shown below as:-

^{32}_{14}Si\rightarrow ^{32}_{15}P+e^-+\bar{v}_e

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Balance the following SYNTHESIS chemical reaction with the correct coefficients:
kolbaska11 [484]

Answer:

b 2,3,1

Explanation:

2 Al + 3 S ----> Al2S3

4 0
3 years ago
An atom of tin has an atomic number of 50 and a mass number of 119. How many protons, electrons, and neutrons are found in one n
jeka94

Answer:

50

Explanation:

atomic number is equivalent to it's protons, electrons and neutrons in a neutral atom

7 0
3 years ago
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Aliun [14]
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Difference between fission and fusion?
algol13
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4 0
3 years ago
30,000 J of heat are added to 23.0 kg of steel to reach a final temperature of 140
kolbaska11 [484]

The initial temperature is 137.34 °C.

<u>Explanation:</u>

As the specific heat formula says that the heat energy required is directly proportional to the mass and change in temperature of the system.

Q = mcΔT

So, here the mass m is given as 23 kg, the specific heat of steel is given as c = 490 J/kg°C and the initial temperature is required to find with the final temperature being 140 °C. Also the heat energy required is 30,000 J.

ΔT =\frac{Q}{mc}

ΔT =\frac{30000}{23 \times 490} = \frac{30000}{11270} =2.66

Since the difference in temperature is 2.66, then the initial temperature will be

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140-Initial temperature = 2.66

Initial temperature = 140-2.66 = 137.34 °C

Thus, the initial temperature is 137.34 °C.

7 0
3 years ago
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