A) can enter from the surroundings, but cannot escape to the surroundings
Answer:
Correct option is B)
According to de-Broglie,
λ=mvh=6.023×10232×5×104cm/sec6.62×10−27ergsec=4×10−8cm=4Ao
Answer:
The correct answer is 0.6 mL.
Explanation:
We use the mathematical expression:
Ci x Vi = Cf x Vf
Where Ci is the initial concentration (5 M); Cf and Vf refers to final concentration (0.002 M) and final volume (1500 mL). With the given data, we calculate the initial volume (Vi):
Vi = (Cf x Vf)/Ci = (0.002 M x 1500 mL)/(5 M) = 0.6 mL
Therefore, we need 0.6 mL of 5 M NaCl to prepare the solution with the requested dilution.
Answer:
See Explanation
Explanation:
Note => 1st one should understand that for an 'acid' to be an acid and a 'base' to be a base, two requirements must be met, (1) the compound must have an ionizable Hydrogen for acids or Hydroxide for bases, and (2) must be in water and ionize delivering H⁺ ions from acids and OH⁻ ions from bases. The Arrhenius acids are characterized by having an ionizable hydrogen which when added into water increases the hydronium ion concentration (H₃O⁺). Arrhenius bases are characterized by having an ionizable hydroxide function (OH-).
Typically, the acids and bases are characterized as either strong or weak electrolytes. the Strong electrolytes ionize 100% in water and Weak electrolytes less than 100%.
The strong acids include HCl, HBr, HI, HNO₃, HClO₄ and H₂SO₄ (1st ionization step). Any acid (H-Anion) not a member of the strong 6 is a weak acid.
The strong Arrhenius Bases are Group IA and Group IIA Hydroxides except for Beryllium Hydroxide. Weak Arrhenius Bases are ammonia or ammonia derivatives (amines) in water.
=> NH₃ + H₂O => NH₄OH ⇄ NH⁺ + OH⁻.
The ammonia derivatives follow the same reactive nature in water.
=> RNH₂ + H₂O => RNH₃OH ⇄ RNH₃⁺ + OH⁻ where R- is a structural substrate; e.g., Methyl Amine => H₃C - NH₂ .
