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kifflom [539]
2 years ago
13

A solution has a pH of 11.75. Calculate the [H:0*] of the solution

Chemistry
1 answer:
Savatey [412]2 years ago
7 0

The [H₃0⁺] of the solution : 1.778  x 10⁻¹² M

<h3>Further explanation  </h3>

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.  

pH = - log [H⁺]  

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.  

A solution whose value is different by n has a difference in the concentration of H⁺ ion of 10ⁿ.  

pH of solution = 11.75

the [H₃0⁺] of the solution :

\tt pH=-log[H_3O^+]\\\\11.75=-log[H_3O^+]\\\\(H_3O^+]=10^{-11.75}=1.778\times 10^{-12}

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\%\text{ composition of element}=\frac{\text{Mass of element}}{\text{Mass of sample}}\times 100

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