1.) Na 
2.) Cl ( at the second blank)
sodium metal+hydrochloric acid
        
             
        
        
        
Answer:
Hey!
Because the organisms habitat has been destroyed, (by many reasons such as Deforestation and Climate Change), the capacity to hold the current population of the plant or animals is declined which can eventually lead to the scenario of EXTINCTION
Explanation:
HOPE THIS HELPS!!
 
        
             
        
        
        
Answer:
 1 mole of sodium chloride ions
Explanation:
i hope this answer helps u 
plz mark me as brainliest
  
        
             
        
        
        
- Telleurium ( Te) is the chemical symbol 
- electron is 52,
 - there are 2 electron in 5s
        
             
        
        
        
Answer:
In the previous section, we discussed the relationship between the bulk mass of a substance and the number of atoms or molecules it contains (moles). Given the chemical formula of the substance, we were able to determine the amount of the substance (moles) from its mass, and vice versa. But what if the chemical formula of a substance is unknown? In this section, we will explore how to apply these very same principles in order to derive the chemical formulas of unknown substances from experimental mass measurements.
Explanation:
tally. The results of these measurements permit the calculation of the compound’s percent composition, defined as the percentage by mass of each element in the compound. For example, consider a gaseous compound composed solely of carbon and hydrogen. The percent composition of this compound could be represented as follows:
\displaystyle \%\text{H}=\frac{\text{mass H}}{\text{mass compound}}\times 100\%%H=
mass compound
mass H
 ×100%
\displaystyle \%\text{C}=\frac{\text{mass C}}{\text{mass compound}}\times 100\%%C=
mass compound
mass C
 ×100%
If analysis of a 10.0-g sample of this gas showed it to contain 2.5 g H and 7.5 g C, the percent composition would be calculated to be 25% H and 75% C:
\displaystyle \%\text{H}=\frac{2.5\text{g H}}{10.0\text{g compound}}\times 100\%=25\%%H=
10.0g compound
2.5g H
 ×100%=25%
\displaystyle \%\text{C}=\frac{7.5\text{g C}}{10.0\text{g compound}}\times 100\%=75\%%C=
10.0g compound
7.5g C
 ×100%=75%