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GrogVix [38]
2 years ago
9

HELP!!!! I cannot find any good answers for this question and I keep getting it wrong! The answer options are:

Mathematics
1 answer:
kondaur [170]2 years ago
8 0

The missing reason is (d) Add the fractions together on the right side of the equation

<h3>How to complete the missing reason?</h3>

From the statements, we have the following equation:

x^2 + b/a x + (b/2a)^2 = -4ac/4a^2 + b^2/4a^2

Next, we add the fractions on the right-hand side of the equation.

This gives

x^2 + b/a x + (b/2a)^2 = [-4ac + b^2]/4a^2

The above means that the last statement is gotten by adding the fractions on the right-hand side of the equation.

Hence, the missing reason is (d) Add the fractions together on the right side of the equation

Read more about quadratic equations at:

brainly.com/question/1214333

#SPJ1

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Step-by-step explanation:

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volume of a cylinder = pi×r^2×h

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The ratio would be 16:14 and then simplify it to 8:7
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3 years ago
Can anyone help with this question
4vir4ik [10]

Answer: A) x=6

Step-by-step explanation: my trick that i do with these questions are to just fill in the x's with the different choices that they give you.

so... first try out 6. fill in every x with a 6. so now, x isn't x anymore, it's 6.

(8-6)=2

9 times 2= 18

3 times 6= 18

this means that x would equal 6

if that first one doesn't work, try out the other ones. but this one works, so we know we have the right answer. i hope this helps with this problem, and i hope it helps with other problems like this too.

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3 0
4 years ago
The volume (in cubic inches) of a shipping box is modeled by V =2x³ -19x² +39x, where x is the length (in inches). Determine the
yawa3891 [41]

Answer:

The values of x for which the model is 0 ≤ x ≤ 3

Step-by-step explanation:

The given function for the volume of the shipping box is given as follows;

V = 2·x³ - 19·x² + 39·x

The function will make sense when V ≥ 0, which is given as follows

When V = 0, x = 0

Which gives;

0 = 2·x³ - 19·x² + 39·x

0 = 2·x² - 19·x + 39

0 = x² - 9.5·x + 19.5

From an hint obtained by plotting the function, we have;

0 = (x - 3)·(x - 6.5)

We check for the local maximum as follows;

dV/dx = d(2·x³ - 19·x² + 39·x)/dx = 0

6·x² - 38·x + 39 = 0

x² - 19/3·x + 6.5 = 0

x = (19/3 ±√((19/3)² - 4 × 1 × 6.5))/2

∴ x = 1.288, or 5.045

At x = 1.288, we have;

V = 2·1.288³ - 19·1.288² + 39·1.288 ≈ 22.99

V ≈ 22.99 in.³

When x = 5.045, we have;

V = 2·5.045³ - 19·5.045² + 39·5.045≈ -30.023

Therefore;

V > 0 for 0 < x < 3 and V < 0 for 3 < x < 6.5

The values of x for which the model makes sense and V ≥ 0 is 0 ≤ x ≤ 3.

8 0
3 years ago
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