From what I learnt so far, there are 3 possible ways of finding whether ratios form a proportion
The maximum value it can be would be 100%. The only times that it could be this high is when there is only a class on the frequency distribution table. Another way, is that there is only one column variable on the table (& or if there is only one row.) Any other time is will be less, but the maximum stays 100%.
Given
- f(n) values for n=1,2,3,4
- possible candidates for the function
Solution:
Method: Evaluate some of the values, for each function. A function with ANY value not matching the given f(n) values will be rejected.
N=1, f(n)=4
f(1)=4-3(1-1)=4
f(1)=4+3^(1+1)=4+3^2=4+9=13 ≠ 4 [rejected]
f(1)=4(3^(n-1))=4(3^0)=4
f(1)=3(4^(n-1))=3(4^0)=3*1=3 [rejected]
N=2, f(n)=12
f(1)=4-3(2-1)=4-3(1)=1 ≠ 12 [rejected]
[rejected]
f(1)=4(3^(2-1)=4*3^1=4*3=12
[rejected]
Will need to check one more to be sure
N=3, f(n)=3
[rejected]
[rejected]
f(3)=4(3^(n-1))=4(3^(3-1))=4(3^2)=4*9=36 [Good]
[rejected]
Solution: f(n)=4(3^(n-1))
Answer is Choice A - 1.
1 times 2 is 2, and 2 + 8 is 10.
Answer:
x < -10/7
Step-by-step explanation:
Divide both sides by -7. Because this divisor is negative, we must reverse the direction of the inequality sign, obtaining:
-7x < 10
----- < -----
-7 -7
Then x < -10/7
