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DiKsa [7]
2 years ago
11

What is the magnitude and direction of the magnetic flux density b within the air?

Physics
1 answer:
ser-zykov [4K]2 years ago
8 0

Magnetic flux density - It is the force acting per unit current per unit length on a wire placed to magnetic field at right angle.

It is denoted by B

unit of B is tesla (T)

                 

The total no. of magnetic field lines passing through a area is called magnetic flux.

Magnitude of the magnetic flux - It is equal to the area of the surface and having perpendicular direction to the plane of the surface.

Its unit is weber (Wb)

Direction to the magnetic flux density - The direction is north pole to the south pole.

The magnetic field lines are known as lines of magnetic flux.

flux lines are not in direction of force but perpendicular.

To know more about magnetic flux density:

brainly.com/question/14236561

#SPJ4

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How do I determine which object has the greatest acceleration?
IceJOKER [234]


To determine which object has the greatest acceleration, you would use the formula:

acceleration = (Final Velocity - Initial Velocity) / Time

Just plug-in values for what you have and see which one has the greatest acceleration. If you're given velocity-time graphs, then the one with the steepest slope would have the greatest acceleration.

8 0
3 years ago
Assume that the average mass of each of the approximately 1 billion people in China is 55 kg.Assume that they all gather in one
Harman [31]

Answer: 5.9(10)^{-8} m

Explanation:

The equation to calculate the center of mass C_{M} of a particle system is:

C_{M}=\frac{m_{1}r_{1}+m_{1}r_{1}+...+m_{n}r_{n}}{m_{1}+m_{2}+...+m_{n}}

In this case we can arrange for one dimension, assuming the geometric center of the Earth and the ladder are on a line, and assuming original center of mass located at the Earth's geometric center:

C_{M}=\frac{m_{E}(0 m) + m_{p} r_{E-p}}{m_{E}+m_{p}}

Where:

m_{E}=5.9(10)^{24} kg is the mass of the Earth

m_{p}=55(10)^{9} kg is the mass of 1 billion people

r_{E}=6371000 m is the radius of the Earth

r_{E-p}=6371000 m- 2m=6370998 m is the distance between the center of the Earth and the position of the people (2 m above the Earth's surface)

C_{M}=\frac{m_{p}55(10)^{9} kg (6370998 m)}{5.9(10)^{24} kg+55(10)^{9} kg}

C_{M}=5.9(10)^{-8} m This is the displacement of Earth's center of mass from the original center.

8 0
3 years ago
A baseball is thrown directly upward from ground level with a velocity of +15 m/s. What are the two times when the ball is 10 m
erastovalidia [21]

Answer:

time is 0.5660 s

and time is - 3.62431  s

Explanation:

velocity u = 15 m/s

height s = 10 m

acceleration due to gravity g =  –9.8 m/s²

to find out

time

solution

we will apply here distance equation that is

s = ut - 1/2× gt²   ...........1

here put all these value and get time t

here s is height and g is -9.8

so

s = ut - 1/2× gt²

10 = 15t - 1/2× (-9.8)t²

10 = 15t + 4.9t²

solve it we get t

t = 0.56630 and -3.62431

so time is 0.5660 s

and time is - 3.62431  s

8 0
4 years ago
An ice skater starts a spin with her arms stretched out to the sides. she balances on the tip of one skate to turn without frict
Georgia [21]
It increases by a factor of 4.
6 0
3 years ago
Read 2 more answers
Consider a spherical planet of uniform density rho. The distance from the planet's center to its surface (i.e., the planet's rad
alisha [4.7K]

Answer:

a) g(r) = 4\pi \cdot G \cdot \rho\cdot r, b) g = 4\pi \cdot G \cdot \rho\cdot r_{P}

Explanation:

a) The acceleration due to gravity inside the planet is:

dg = G\cdot \frac{\rho \cdot dV}{r^{2}}

dg = G\cdot \frac{\rho \cdot dV}{r^{2}}

dg = G\cdot \frac{4\pi\cdot \rho \cdot r^{2}\,dr}{r^{2}}

dg = 4\pi\cdot G\cdot \rho \,dr

g(r) = 4\pi \cdot G \cdot \rho\cdot r

b) The acceleration at the surface of the planet is:

g = 4\pi \cdot G \cdot \rho\cdot r_{P}

5 0
3 years ago
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