A baseball is thrown directly upward from ground level with a velocity of +15 m/s. What are the two times when the ball is 10 m above ground level? Take acceleration due to gravity to be –9.8 m/s^2 .
1 answer:
Answer:
time is 0.5660 s
and time is - 3.62431 s
Explanation:
velocity u = 15 m/s
height s = 10 m
acceleration due to gravity g = –9.8 m/s²
to find out
time
solution
we will apply here distance equation that is
s = ut - 1/2× gt² ...........1
here put all these value and get time t
here s is height and g is -9.8
so
s = ut - 1/2× gt²
10 = 15t - 1/2× (-9.8)t²
10 = 15t + 4.9t²
solve it we get t
t = 0.56630 and -3.62431
so time is 0.5660 s
and time is - 3.62431 s
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Answer:
Answered
Explanation:
x= 0.02 m
E_p= 10.0 J
E_p= 0.5kx^2
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solving we get
K= 50.0 N/m
Now
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