Answer:
It's a quantitative observation because it includes numerical data.
Explanation:
please mark brainliest if im correct
Answer:
By a factor of 9/4
Explanation:
Applying Coulomb's law,
F = kqq'/r²................... Equation 1
Assuming q and q' are the two point charges respectively.
Where k = coulomb's constant, r = distance between the charges.
When the point charges are 3.0 m apart,
F = kqq'/3²
F = kqq'/9.................... Equation 1
When they are moved to a new distance, 2.00 m
F' = kqq'/2²
F' = kqq'/4................. Equation 2.
Comparing equation 1 and equation 2.
F' = 9F/4
Hence the resulting mutual force change by a factor of 9/4
A transform fault boundary is the correct answer.
Answer:
0.465 kgm/s
Explanation:
Given that
Mass of the cart A, m1 = 450 g
Speed of the cart A, v1 = 0.85 m/s
Mass of the cart B, m2 = 300 g
Speed of the cart B, v2 = 1.12 m/s
Now, using the law of conservation of momentum.
It is worthy of note that our cart B is moving in opposite directions to A
m1v1 + m2v2 =
(450 * 0.85) - (300 * 1.12) =
382.5 - 336 =
46.5 gm/s
If we convert to kg, we have
46.5 / 100 = 0.465 kgm/s
Thus, the total momentum of the system is 0.465 kgm/s
