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nikklg [1K]
2 years ago
14

Light of a given wavelength is used to illuminate the surface of a metal, however, no photoelectrons are emitted. In order to ca

use electrons to be ejected from the surface of this metal you should?
Physics
1 answer:
Anastasy [175]2 years ago
4 0

In order to cause electrons to be ejected from the surface of this metal you should use light of a shorter wavelength.

The photoelectric effect is the emission of electrons when electromagnetic radiation, such as light, hits a material. Electrons emitted in this manner are called photoelectrons. The phenomenon is studied in condensed matter physics, and solid state and quantum chemistry to draw inferences about the properties of atoms, molecules and solids. The effect has found use in electronic devices specialized for light detection and precisely timed electron emission.

This process is also often referred to as photoemission. In terms of their behaviour and their properties, photoelectrons are no different from other electrons. The prefix, photo-, simply tells us that the electrons have been ejected from a metal surface by incident light.

The photons of a light beam have a characteristic energy, called photon energy, which is proportional to the frequency of the light. In the photoemission process, when an electron within some material absorbs the energy of a photon and acquires more energy than its binding energy, it is likely to be ejected. If the photon energy is too low, the electron is unable to escape the material. Since an increase in the intensity of low-frequency light will only increase the number of low-energy photons, this change in intensity will not create any single photon with enough energy to dislodge an electron. Moreover, the energy of the emitted electrons will not depend on the intensity of the incoming light of a given frequency, but only on the energy of the individual photons.

Learn more about Photoelectric effect here : brainly.com/question/1408276

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A student exerts a force of 500 n pushing a box 10 m across the floor in 4 s. how much work does the student perform?
gregori [183]
Work = Force * distance
W = Fd

Given F = 500 N, d = 10 m
W = (500)(10)
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The work done is 500 Joules. The time of 4 s is irrelevant in this case.
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3 years ago
Determine the change in thermal energy of 100 g of copper (M = 63,5, Debye 348K) if it is cooled from
Setler [38]

Answer:

given,

mass of copper = 100 g

latent heat of liquid (He) = 2700 J/l

a) change in energy

Q = m Cp (T₂ - T₁)

Q = 0.1 × 376.812 × (300 - 4)

Q = 11153.63 J

He required

Q = m L

11153.63 = m × 2700

m = 4.13 kg

b) Q = m Cp (T₂ - T₁)

Q = 0.1 × 376.812 × (78 - 4)

Q = 2788.41 J

He required

Q = m L

2788.41 = m × 2700

m = 1.033 kg

c) Q = m Cp (T₂ - T₁)

Q = 0.1 × 376.812 × (20 - 4)

Q = 602.90 J

He required

Q = m L

602.9 = m × 2700

m =0.23 kg

8 0
3 years ago
Which of the following is neutral?
Sauron [17]

Answer:

atoms and neutrons

Explanation:

electrons have a negative charge

protons have a positive charge

cations are positive ions

anions are negative ions

4 0
3 years ago
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