Pls help! <br> What is movement of energy from one system to another also known as?

Consider four point charges arranged in a square with sides of length L. Three of the point charges have charge q and one of the

nydimaria [60]

Answer: $F_{net}=\frac{kq^2}{(L)^2}\left [ \frac{1}{2}+\sqrt{2}\right ]$

Explanation:

Given

Three charges of magnitude q is placed at three corners and fourth charge is placed at last corner with -q charge

Force due to the charge placed at diagonally opposite end on -q charge

$F_1=\frac{kq(-q)}{(L\sqrt{2})^2}$

where $L\sqrt{2}=$ Distance between the two charges

$F_1=-\frac{kq^2}{2L^2}$

negative sign indicates that it is an attraction force

Now remaining two charges will apply the same amount of force as they are equally spaced from -q charge

$F_2=\frac{kq(-q)}{(L)^2}$

The magnitude of force by both the charge is same but at an angle of $90^{\circ}$

thus combination of two forces at 2 and 3 will be

$F'=\sqrt{2}\frac{kq^2}{2L^2}$

Now it will add with force due to 1 charge

Thus net force will be

$F_{net}=\frac{kq^2}{(L)^2}\left [ \frac{1}{2}+\sqrt{2}\right ]$

6 0

3 years ago

A man does 4,475 J of work in the process of pushing his 2.50 103 kg truck from rest to a speed of v, over a distance of 26.0 m.

Tcecarenko [31]

Answer:

a) 1.89 m/s b) 172.1 N

Explanation:

a)

Applying the work-energy theorem, if we can neglect the friction between truck and road, the total change in kinetic energy must be equal to the work done by the external forces.
This work, is just 4,475 J.
So we can write the following equation:

$\Delta K = \frac{1}{2} * m*v^{2} = 4,475 J$

where m= mass of the truck = 2.5*10³ kg.
So, we can find the speed v, as follows:

$v =\sqrt{\frac{2*W}{m}} =\sqrt{\frac{2*4,475J}{2.5e3kg} } = 1.89 m/s$

b)

The work done by the man, is just the horizontal force applied, times the displacement produced by the force horizontally:

$W = F*d$

We can solve for F, as follows:

$F = \frac{W}{d} = \frac{4,475 J}{26.0m} = 172.1 N$

4 0

3 years ago

describe at least two ways in which parents are able to influence the drinking habits of their children

laiz [17]

Well parents can set rules or even punishments which can influence the drinking habits of there kids such as, they aren't allowed to go out unless they had followed the rule there parents set for the amount they needed to have drank. Parents have many ways in which there authority can influence there kids habits.

6 0

3 years ago

Read 2 more answers

According to Newton's first law, which characteristic of a moving object would remain constant if there were no other

suter [353]

In object in motion stays in motion; speed

8 0

3 years ago

A,b, e are complete. Help on the others would be so appreciated!!

bixtya [17]

Answer:

serie Ceq=0.678 10⁻⁶ F and the charge Q = 9.49 10⁻⁶ C

Explanation:

Let's calculate all capacity values

a) The equivalent capacitance of series capacitors

1 / Ceq = 1 / C1 + 1 / C2 + 1 / C3 + 1 / C4 + 1 / C5

1 / Ceq = 1 / 1.5 + 1 / 3.3 + 1 / 5.5 + 1 / 6.2 + 1 / 6.2

1 / Ceq = 1 / 1.5 + 1 / 3.3 + 1 / 5.5 + 2 / 6.2

1 / Ceq = 0.666 + 0.3030 +0.1818 +0.3225

1 / Ceq = 1,147

Ceq = 0.678 10⁻⁶ F

b) Let's calculate the total system load

Dv = Q / Ceq

Q = DV Ceq

Q = 14 0.678 10⁻⁶

Q = 9.49 10⁻⁶ C

In a series system the load is constant in all capacitors, therefore, the load in capacitor 5.5 is Q = 9.49 10⁻⁶ C

c) The potential difference

ΔV = Q / C5

ΔV = 9.49 10⁻⁶ / 5.5 10⁻⁶

ΔV = 1,725 V

d) The energy stores is

U = ½ C V²

U = ½ 0.678 10-6 14²

U = 66.4 10⁻⁶ J

e) Parallel system

Ceq = C1 + C2 + C3 + C4 + C5

Ceq = (1.5 +3.3 +5.5 +6.2 +6.2) 10⁻⁶

Ceq = 22.7 10⁻⁶ F

f) In the parallel system the voltage is maintained

Q5 = C5 V

Q5 = 5.5 10⁻⁶ 14

Q5 = 77 10⁻⁶ C

g) The voltage is constant V5 = 14 V

h) Energy stores

U = ½ C V²

U = ½ 22.7 10-6 14²

U = 2.2 10⁻³ J

8 0

3 years ago

Pls help! What is movement of energy from one system to another also known as?