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Paraphin [41]
1 year ago
8

Suppose that you measure the length of a spaceship, at rest relative to you, to be 400 m. how long will you measure it to be if

it flies past you at a speed of u=0.75c
Physics
1 answer:
Fantom [35]1 year ago
8 0

Calculate the length of a spaceship as follows:

l = l₀√1 - v²/c²

=(400 m)√1 - (0.75c)2 c²

=264.575m.

The Spaceship Origin Portfolio is an index fund that invests in listed Australian and global equities by market capitalization. Invest in the top 100 Australian and top 100 international companies.

Starships, also known as star cruisers, starships, spacecraft, or simply starships or ships, were vessels designed specifically for interstellar travel between star systems.

For clients in the Spaceship Index portfolio, the situation is a little different. The Spaceship Index portfolio consists of approximately 100 of his ASX-listed companies with the largest market capitalization and approximately 100 global companies with the largest market capitalization.

Learn more about spaceship at

brainly.com/question/28175986

#SPJ4

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7 0
2 years ago
Buoyant force is the net upward force that affects on the object in a fluid
Katarina [22]

Answer:True

Explanation:

Buoyant force is the net upward force, that affect on the object in a fluid

4 0
3 years ago
6.) What is
Feliz [49]

Answer:

100 V

Explanation:

Hi there!

Ohm's law states that V=IR where V is the voltage, I is the current and R is the resistance.

Plug the given information into Ohm's law (R=50, I=A)

V=IR\\V=(2)(50)\\V=100

Therefore, the voltage across this current is 100 V.

I hope this helps!

6 0
2 years ago
Which of the following is true about wedges?
timofeeve [1]

Answer:

wedges are a type of inclined plane.

Explanation:

i just answered :) :) :)

8 0
3 years ago
Con lắc lò xo có độ cứng k = 100N/m được gắn vật có khối lượng m=0.1kg, kéo vật ra khỏi vị trí cân bằng 1 đoạn 5cm rồi buông tay
Delvig [45]

Answer:

The maximum velocity is 1.58 m/s.

Explanation:

A spring pendulum with stiffness k = 100N/m is attached to an object of mass m = 0.1kg, pulls the object out of the equilibrium position by a distance of 5cm, and then lets go of the hand for the oscillating object. Calculate the achievable vmax.

Spring constant, K = 100 N/m

mass, m = 0.1 kg

Amplitude, A = 5 cm = 0.05 m

Let the angular frequency is w.

w = \sqrt{K}{m}\\\\w = \sqrt{100}{0.1}\\\\w = 31.6 rad/s

The maximum velocity is

v_{max} = w A\\\\v_{max} = 31.6\times 0.05 = 1.58 m/s

8 0
3 years ago
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