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Paraphin [41]
2 years ago
8

Suppose that you measure the length of a spaceship, at rest relative to you, to be 400 m. how long will you measure it to be if

it flies past you at a speed of u=0.75c
Physics
1 answer:
Fantom [35]2 years ago
8 0

Calculate the length of a spaceship as follows:

l = l₀√1 - v²/c²

=(400 m)√1 - (0.75c)2 c²

=264.575m.

The Spaceship Origin Portfolio is an index fund that invests in listed Australian and global equities by market capitalization. Invest in the top 100 Australian and top 100 international companies.

Starships, also known as star cruisers, starships, spacecraft, or simply starships or ships, were vessels designed specifically for interstellar travel between star systems.

For clients in the Spaceship Index portfolio, the situation is a little different. The Spaceship Index portfolio consists of approximately 100 of his ASX-listed companies with the largest market capitalization and approximately 100 global companies with the largest market capitalization.

Learn more about spaceship at

brainly.com/question/28175986

#SPJ4

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Physical values in the real world have two componnts: magnitude and ____
Dahasolnce [82]

Answer:

DIRECTION

Explanation:

3 0
3 years ago
Compare green and orange light from the visible spectrum. You are currently in a labeling module. Turn off browse mode or quick
77julia77 [94]

Green: nm 495–570. Yellow: nm 570–590. 590–620 nm for orange. Red: 620-750 nm (400–484 THz frequency)

Solids' molecules are strongly attracted to one another. As a result, the molecules are barely moving and tightly packed. Because of this, shape and volume are fixed.

The forces of attraction and repulsion in liquids are comparable. Compared to the solid state, they move a little bit more. They then assume the shape of the container while still having a fixed capacity.

The attraction forces between the molecules in gases are quite weak. They move quite freely and grow in an effort to fill as much space as they can. Consequently, their volume and shape vary (adopt the shape of the container).

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6 0
2 years ago
How does inertia affect a person who is not wearing a seatbelt during a collision?
ELEN [110]

A person who is not wearing a seatbelt during a collision will be thrown forward because it maintains forward motion

<h3>Further explanation </h3>

In Newton's law, it is stated that if the resultant force acting on an object of magnitude is zero,  it can be formulated :

\large{\boxed{\bold{\Sigma F = 0}}}

then the object tends to defend itself from its state. So for objects in a state of movement, objects tend to move forever. Likewise, for objects in a state of rest, they tend to remain forever. The tendency of objects like this is called<em> inertia </em>

The size of inertia is proportional to mass, the greater the mass of the object, the greater the inertia of the object.

In objects with mass m that move translatively, the object will maintain its linear velocity

When we are in a vehicle that moves forward, then we will still maintain a state of forwarding motion. If our vehicle stops suddenly, then we keep moving forward so we will be pushed forward. From this point, the use of a safety belt serves to hold back our movements so that there are no fatal accidents or collisions.

<h3>Learn more </h3>

Newton's law of inertia

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example of Newton's First Law of inertia

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Keywords: inertia, Newton's First Law

7 0
3 years ago
Read 2 more answers
A mass of 1000 kg drops from a height of 10 m on a platform of negligible mass. It is desired to design a spring and dashpot on
Juliette [100K]

Answer:

k = 5\times 10^{4}\ N/m

b = 0.707\times 10^{3}

t = 7.1\times 10^{- 5}\ s

Solution:

As per the question:

Mass of the block, m = 1000 kg

Height, h = 10 m

Equilibrium position, x = 0.2 m

Now,

The velocity when the mass falls from a height of 10 m is given by the third eqn of motion:

v^{2} = u^{2} + 2gh

where

u = initial velocity = 0

g = 10m/s^{2}

Thus

v = \sqrt{2\times 10\times 10} = 10\sqrt{2}\ m/s

Force on the mass is given by:

F = mg = 1000\times 10 = 10000 N = 10\ kN

Also, we know that the spring force is given by:

F = - kx

Thus

k = \frac{F}{x} = \frac{10000}{0.2} = 5\times 10^{4}\ N/m

Now, to find the damping constant b, we know that:

F = - bv

b = \frac{F}{v} = \frac{10000}{10\sqrt{2}} = 0.707\times 10^{3}

Now,

Time required for the platform to get settled to 1 mm or 0.001 m is given by:

t = \frac{0.001}{v} = \frac{0.001}{10\sqrt{2}} = 7.1\times 10^{- 5}\ s

4 0
3 years ago
A 5 kg rock is lifted 3m find amount of work done <br><br> a= 98 J
Levart [38]

Answer:

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