Answer:
When we double the angular velocity the maximum acceleration will changes by a factor of 4.
Explanation:
Given the angular frequency of the simple harmonic oscillator is doubled.
We need to find the change in the maximum acceleration of the oscillator.
Now, according to the problem, the angular frequency got doubled.
Let us plug . Then the maximum acceleration will be
We can see, when we double the angular velocity the maximum acceleration will changes by a factor of 4.
An impact which stops a moving object must do enough work to take away its kinetic energy, so extending the distance moved during the collision reduces the impact force.
D. Heat energy will be transferred within the system and if left long enough, there will be enough transferred energy to make both of them the same temperature.
Answer:
The angular frequency of the block is ω = 5.64 rad/s
Explanation:
The speed of the block v = rω where r = amplitude of the oscillation and ω = angular frequency of the oscillation.
Now ω = v/r since v = speed of the block = 62 cm/s and r = the amplitude of the oscillation = 11 cm.
The angular frequency of the oscillation ω is
ω = v/r
ω = 62 cm/s ÷ 11 cm
ω = 5.64 rad/s
So, the angular frequency of the block is ω = 5.64 rad/s
When you know both the speed and direction of an object’s motion, you know the velocity of an object. speed in a given direction is called velocity
hope this helps :)