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3 years ago

On the position-time graph, what is the average velocity between 5 s and 10 s?

Physics

1 answer:

Stells [14]3 years ago

5 0

For this case, we observe that in the interval of 5 to 10 seconds the behavior of the function is linear. Therefore, the average speed in that interval will be given by the slope of the line. This can be calculated as follows
m = (y2-y1) / (x2-x1)
Substituting the values of points A and C
m = ((30) - (10)) / ((10) - (5)) = 4
answer
the average velocity between 5 s and 10 s is 4m / s
B. +4.0 m / s

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where

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d is the distance between the plates

Here, the radius of each plate is

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so the area is

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While the separation between the plates is

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So the capacitance is

$C=\frac{(8.85\cdot 10^{-12} F/m)(3.14\cdot 10^{-4} m^2)}{5\cdot 10^{-4} m}=5.56\cdot 10^{-12} F$

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The magnitude of the electric field is given by

$E=\frac{V}{d}=\frac{200 V}{5\cdot 10^{-4} m}=4\cdot 10^5 V/m$

and the energy density of the electric field is given by

$u=\frac{1}{2}\epsilon_0 E^2$

and using

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Given

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$v_{min}=\sqrt{15.68}$

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