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2 years ago

A object was fired at 17ms at 40 degree angle horizontal , if object traveled 29meters how long was it in the air

1 answer:

8 0

First you need to find the initial x component which is 13.02. After that you plug it into the 3rd formula on the AP physics formula sheet. Then rearrange it into the quadratic formula and solve for time. The answer should be 4.1 seconds.

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A block weighing 10 newtons is resting on a plane inclined 30° to the horizontal. What is the magnitude of the normal force acti

aleksley [76]

Magnitude of normal force acting on the block is 7 N

Explanation:

10N = 1.02kg

Mass of the block = m = 1.02 kg

Angle of incline Θ = 30°

Normal force acting on the block = N

From the free body diagram,

N = mgCos Θ

N = (1.02)(9.81)Cos(30)

N = 8.66 N

Rounding off to nearest whole number,

N = 7 N

Magnitude of normal force acting on the block = 7 N

7 0

3 years ago

What is in the universe

svp [43]

Everything is in the universe.
That's what the word means.

5 0

3 years ago

Read 2 more answers

What is the density of 18.0-karat gold that is a mixture of 18 parts gold, 5 parts silver, and 1 part copper? (These values are

nexus9112 [7]

Answer:

Density of 18.0-karat gold mixture is $15.58 g/cm^3$ .

Explanation:

A mixture of 18 parts gold, 5 parts silver, and 1 part copper.

Let mass of gold be 18x

Let the mass of silver be 5x

Let the mass of copper be 1x

The density of gold = $19.32g/cm^3$

The density of silver = $10.1g/cm^3$

The density of copper = $8.8g/cm^3$

$Volume=\frac{Mass}{Density}$

Volume of the gold in the mixture = $V_1=\frac{18x}{19.32 g/cm^3}$

Volume of the silver in the mixture = $V_2=\frac{5x}{10.1 g/cm^3}$

Volume of the copper in the mixture = $V_3=\frac{1x}{8.8 g/cm^3}$

Mass of the mixture = M = 18x+5x+1x =24x

Volume of the mixture = $V_1+V_2+V_3$

Density of the mixture:

$\frac{M}{V_1+V_2+V_3}=15.58 g/cm^3$

8 0

3 years ago

A toy car on a string is pulled across a table horizontally. The string is at an angle

ddd [48]

Which way is it being pulled?

6 0

3 years ago

Two cylindrical resistors are made of the same material and have the same resistance. The resistors, R1 and R2, have different r

Paladinen [302]

Answer:

Option d is correct.

Explanation:

We know , resistance of a body is directly proportional to its length and inversely proportional to its area.

$R=\dfrac{\rho\ L}{A}=\dfrac{\rho\ L}{\pi r^2}$ ( Here, $\rho$ is constant dependent on object material )

Writing $R_1 \ and\ R_2$ also :

$R_1=\dfrac{\rho\ L_1}{\pi r_1^2}\ , \ R_2=\dfrac{\rho\ L_2}{\pi r_2^2}$ ( since they are of same material therefore, $\rho$ is same.)

Now , if $r_2=2r_1 \ and \ 4L_1=L_2$ .

Then $R_1=R_2$

Therefore, option d. is correct.

Hence, this is the required solution.

7 0

3 years ago