Answer:
Volume of container = 0.0012 m³ or 1.2 L or 1200 ml
Explanation:
Volume of butane = 5.0 ml
density = 0.60 g/ml
Room temperature (T) = 293.15 K
Normal pressure (P) = 1 atm = 101,325 pa
Ideal gas constant (R) = 8.3145 J/mole.K)
volume of container V = ?
Solution
To find out the volume of container we use ideal gas equation
PV = nRT
P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
First we find out number of moles
<em>As Mass = density × volume</em>
mass of butane = 0.60 g/ml ×5.0 ml
mass of butane = 3 g
now find out number of moles (n)
n = mass / molar mass
n = 3 g / 58.12 g/mol
n = 0.05 mol
Now put all values in ideal gas equation
<em>PV = nRt</em>
<em>V = nRT/P</em>
V = (0.05 mol × 8.3145 J/mol.K × 293.15 K) ÷ 101,325 pa
V = 121.87 ÷ 101,325 pa
V = 0.0012 m³ OR 1.2 L OR 1200 ml
Answer:
Explanation:
Hello!
In this case, since the molar mass of a chemical compound is computed by averaging the atomic mass of each element in the molecule and the amount of atoms; which in this case there are 9 carbon atoms, 13 hydrogen atoms, 1 nitrogen atom and 3 oxygen atoms; thus, we compute the average as shown below:
Now, we plug in the atomic masses to obtain:
Best regards!
Answer:
HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)
Explanation:
Aqueous solution of HCl and aqueous solution of KOH react as follow:
HCl(aq) + KOH(aq) —>
In solution, HCl and KOH will dissociates as follow:
HCl —> H+ + Cl-
KOH —> K+ + OH-
During the reaction, a double displacement reaction occur as shown below:
H+ + Cl- + K+ + OH- —> K+Cl- + H+OH-
The elemental equation is given below:
HCl(aq) + KOH(aq) —> KCl(aq) + H2O(l)
They are different beacause of the stages some you can see and not. And the cells move at different paces
They break down dead organisms
