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Mariulka [41]
1 year ago
15

when solid pellets of sodium hydroxide (naoh) dissolve in water, the temperature of the water can rise dramatically. taking naoh

as the system, what can you deduce about the signs of the entropy change of the system (δssys) and surroundings (δssurr) from this?
Chemistry
1 answer:
irga5000 [103]1 year ago
8 0

ΔSsys  and ΔSsurr both have values larger than 0.

<h3>Entropy Change: What Is It?</h3>
  • Entropy change is a phenomena that measures the evolution of randomness or disorder in a thermodynamic system.
  • It has to do with how heat or enthalpy is converted during work.
  • More unpredictability in a thermodynamic system indicates high entropy.
  • Heat transport (delta Q) divided by temperature equals the change in entropy (delta S).
<h3>What causes variations in entropy?</h3>
  • When a substance is divided into several pieces, entropy rises.
  • Because the solute particles are split apart when a solution is generated, the dissolving process increases entropy.
  • As the temperature rises, entropy increases.

learn more about entropy change here

brainly.com/question/6364271

#SPJ4

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The ph of 0.015 m hno2 (nitrous acid) aqueous solution was measured to be 2.63. what is the value of pka of nitrous acid?
Licemer1 [7]
Nitrous acid<span> dissociates as follows:
</span>
HNO₂(s) ⇄ H⁺(aq) + NO₂⁻(aq) 
           
According to the equation, an acid constant has the following form:

Ka = [H⁺] × [NO₂⁻ ] / [HNO₂] 

From pH, we can calculate the concentration of H⁺ and NO₂⁻:

[H⁺] = 10^-pH = 10^-2.63 = 0.00234 M = [NO₂⁻]

Now, the acid constant can be calculated:

Ka = 0.00234 x 0.00234 / 0.015  = 3.66 x 10⁻⁴

And finally,

pKa = -log Ka = 3.44 


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