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Elza [17]
3 years ago
9

00000044m 300000km/s Both in scientific notation

Chemistry
1 answer:
cupoosta [38]3 years ago
5 0

Answer:

4.4 × 10^-7

3 × 10^5

Explanation:

scmack me wit dat brainliest

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What does the first word in the name of a binary ionic compound represent?
igomit [66]

Answer:

The name of the cation

Explanation:

The name of a binary ionic compound is

name_of_cation name_of_anion

Thus, the first part of the name is the name of the cation.

For example, the first part of the name of Na⁺Cl⁻ is sodium.

5 0
4 years ago
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What is the wavelength of a light that has a frequency of 5.00x10 to the 12 power s negative 1 power
Lilit [14]

The wavelength of the light is 6.00 × 10^(-5) m.

The formula connecting frequency <em>f</em> and wavelength λ is

<em>f</em>λ = <em>c</em>

where <em>c</em> = the speed of light [2.998 × 10^8 m·s^(-1)]

We can rearrange the formula to get

λ = <em>c</em>/<em>f </em>

∴ λ = 2.998 × 10^10 m·s^(-1)/5.00 × 10^12 s^(-1) = 6.00 × 10^(-5) m = 60.0 µm

4 0
4 years ago
Why are experimental investigations the best type of
vladimir2022 [97]

Answer:

Experimental investigations are the best type of scientific research to demonstrate the relationships between cause and effect because they allow the investigator to actively manipulate variables and control conditions. This change can be measured to gather evidence to back up or refute the relationship between cause and effect.

5 0
4 years ago
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Decane (C10H22) is used in diesel. The combustion for decane follows the equation: 2 C10H22 + 31 O2 à 20 CO2 + 22 H2O. Calculate
creativ13 [48]

The mass of water produced is 792 grams by the combustion of 568 grams of decane.

Given:

Combustion of 568 grams of decane with 2979 grams of oxygen.

2 C_{10}H_{22 }+ 31 O_2 \rightarrow 20 CO_2 + 22 H_2O

To find:

The mass of water produced by combustion of 568 grams of decane.

Solution:

Mass of decane = 568 g

Moles of decane :

= \frac{568 g}{142 g/mol}=4 mol

Mass of oxygen gas = 2976 g

Moles of oxygen gas:

= \frac{2976 g}{32 g/mol}=93 mol

2 C_{10}H_{22 }+ 31 O_2 \rightarrow 20 CO_2 + 22 H_2O

According to reaction, 2 moles of decane reacts with 31 moles of oxygen, then 4 moles of decane will react with:

=\frac{31}{2}\times 4mol=62\text{ mol of}O_2

But according to the question, we have 93.0 moles of oxygen gas which is more than 62 moles of oxygen gas.

So, this means that oxygen gas is present in an excessive amount. Which simply means:

  • Oxygen gas is an excessive reagent.
  • Decane is a limiting reagent.
  • Decane being limiting reagent will be responsible for the amount of water produced after the reaction.

According to reaction, 22 moles of water is produced from 2 moles of decane, then 4 moles of decane will produce:

=\frac{22}{2}\times 4mol=44\text{mol of }H_2O

Mass of 44 moles of water ;

=44mol\times 18g/mol=792g

792 grams of water is produced by the combustion of 568 grams of decane.

Learn more about limiting reagent and excessive reagent here:

brainly.com/question/14225536?referrer=searchResults

brainly.com/question/7144022?referrer=searchResults

3 0
3 years ago
If a particle has Z = 25 and 23 electrons, what is its charge?
Anton [14]

Answer:- The charge is +2.

Explanations:- Z stands for atomic number. The Z is given as 25 means the atomic number of the element is 25. It has 23 electrons. For a neutral atom the number of electrons is same as the atomic number. Since the number of electrons is less than atomic number, the atom must have lost the electrons.

Number of electrons lost = 25 - 23 = 2

If the element lost electrons then it has positive charge. As, the electrons are lost, the charge is +2.



3 0
3 years ago
Read 2 more answers
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