00000044m<br> 300000km/s <br> Both in scientific notation

Which element, if combined with chlorine, will have the greatest attraction for the chlorine electrons? N P As

Mumz [18]

Basically, the answer for this would be N or NITROGEN. If we combine nitrogen with chlorine, what happens is that, it can attract more chlorine electrons towards itself. The reason is that, nitrogen is considered more electronegative compared to chlorine. So best answer for this is the first option.

5 0

3 years ago

Read 2 more answers

HELP!!! DUE TONIGHT!!

IRINA_888 [86]

Answer:

K I will attempt

Explanation:

a)

$O_2_{(g)}+ 2H_2_{(g)} => 2H_2O_{(l)}\\$

b)

1 : 2 : 2 (I don't know if this is what the question wants but it is what I would answer)

c)

Hydrogen because it requires 2 moles of H2 to react with 1 mole of O2

d)

24 moles of water. Look at stoichiometric coefficient. 2:2 means 24 moles you get 24 moles

e)

Oxygen. 2 < 5/2. Remember, 1 mole of O2 requires 2 moles of H2. But 5/2 is still greater than 2

f)

First, let's find out how many moles of water we can get. Since O2 is the limiting reactant, and O2:H2O ratio is 1:2, we will get 4 moles of H2O. Then, we can multiply 4 by Avogadro's number which is $6.022*10^{23}$ to get the number of molecules. We get: 2.41 * 10^24 molecules of water.

6 0

2 years ago

Read 2 more answers

Be sure to answer all parts. Butane gas is compressed and used as a liquid fuel in disposable cigarette lighters and lightweight

Salsk061 [2.6K]

Answer:

The correct answer will be "4.60 g".

Explanation:

The given values are:

Volume of Butane = 7.96 mL

Density = 0.579 g/mL

As we know,

⇒ $Mass \ of \ Butane = Density\times Volume$

On putting the estimated values, we get

⇒ $=0.579\times 7.96$

⇒ $=4.60 \ g$

6 0

3 years ago

Codeine C18H21NO3 is a weak organic base. A 5.0 x 10^-3 M solution of codeine has a pH of 9.95. Calculate the value of Kb for th

arsen [322]

Answer:

Kb = $4.45\times10^{-7}\ mol/L$

$p^{Kb}=6.35$

Explanation:

For a weak organic base, the formula to find $p^{OH}$ is given by:

$p^{OH}=p^{K_b}+\log c$

where c is the concentration of base.

Here c= $5\times10^{-3}\ M$

$p^{H}=9.95\\p^{OH}=14-p^{H}=14-9.95=4.05$

Substituting the above values in the formula,we get:

$p^{k_b}=p^{OH}-\log c\\p^{k_b}=4.05-\log (5\times10^{-3})\\p^{K_b}=6.35\\K_b=$antilog 6.35=4.45\times10^{-7}\ mol/L$

Hence:

Kb = $4.45\times10^{-7}\ mol/L$

$p^{Kb}=6.35$

7 0

3 years ago

A closed vessel having a volume of 1 liter holds 2.5 × 1022 molecules of carbon dioxide gas. Determine the mass of CO2 present,

11111nata11111 [884]

Answer:

mass = 1.8x10⁻³ kg; number of moles = 4.1x10⁻⁵ kmol; specific volume = 0.55 m³/kg; molar specific volume = 24.4 m³/kmol

Explanation:

By the Avogadro's number, 1 mol of the matter has 6.02x10²³ molecules, thus, the number of moles (n) is the number of molecules presented divided by Avogadro's number:

n = 2.5x10²²/6.02x10²³

n = 0.041 mol

n = 4.1x10⁻⁵ kmol

The molar mass of CO₂ is 44 g/mol (12 g/mol of C + 2*16g/mol of O), and the mass is the number of moles multiplied by the molar mass:

m = 0.041 mol * 44 g/mol

m = 1.804 g

m = 1.8x10⁻³ kg

The specific volume (v) is the volume (1L = 0.001 m³) divided by the mass, and it represents how much volume is presented in each part of the mass:

v = 0.001/1.8x10⁻³

v = 0.55 m³/kg

The molar specific volume (nv) is the volume divided by the number of moles, and it represents how much volume is presented in each part of the mol:

nv = 0.001/4.1x10⁻⁵

nv = 24.4 m³/kmol

5 0

3 years ago

00000044m 300000km/s Both in scientific notation