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DENIUS [597]
3 years ago
12

Which of these are physical changes in matter check all that apply . ​

Chemistry
2 answers:
sergeinik [125]3 years ago
7 0

What answers are there? you didn't add them.

physical change and chemical change.

physical change affects a substance's physical properties, and a chemical change affects its chemical properties.

Orlov [11]3 years ago
6 0

Answer:

boiling water

sharpening a pencil

freezing water

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5.25 ml of substance A has a mass of 3.9 g and 6.24 ml of substance B has a mass of 4.4 g. Which liquid is more dense?
Viktor [21]
Substance A because it weighs less
5 0
2 years ago
Calculate the molar concentration of the Cl⁻ ions in 0.92 M MnCl2(aq).
scZoUnD [109]
MnCl2(aq) is an ionic compound which will have the releasing of 2 Cl⁻ ions ions in water for every molecule of MnCl2 that dissolves.
MnCl2(s) --> Mn+(aq) + 2 Cl⁻(aq)
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4 0
3 years ago
Can somebody help me please
LenaWriter [7]

Answer:

0.1139952 is the answer

Explanation:

4 0
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if a leaf falls from a tree we assume that it is in free fall and not affected by air resistance, how many force vectors does th
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3 years ago
Assume the molality of isoborneol in your product is 0.275 mol/kg. What is the melting point of your impure sample given that th
aliina [53]

Answer:

168°C is the melting point of your impure sample.

Explanation:

Melting point of pure camphor= T =179°C

Melting point of sample = T_f = ?

Depression in freezing point = \Delta T_f

Depression in freezing point  is also given by formula:

\Delta T_f=i\times K_f\times m

K_f = The freezing point depression constant

m = molality of the sample  = 0.275 mol/kg

i = van't Hoff factor

We have: K_f = 40°C kg/mol

i = 1 (  non electrolyte)

\Delta T_f=1\times 40^oC kg/mol\times 0.275 mol/kg

\Delta T_f=11^oC

\Delta T_f=T- T_f

T_f=T- \Delta T_f=179^oC-11^oC=168^oC

168°C is the melting point of your impure sample.

4 0
3 years ago
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