All categories

1 year ago

Question 1: find Y if 3 1/3 of Y is 60 Question 2: find x if 11/5 of x is 55

Mathematics

1 answer:

Natasha_Volkova [10]1 year ago

6 0

Question 1

$3 \frac{1}{3} Y=60 \\ \\ \frac{10}{3} Y=60 \\ \\ Y=\frac{60 \cdot 3}{10} \\ \\ Y=18$

Question 2

$\frac{11}{5}x=55 \\ \\ x=\frac{55 \cdot 5}{11} \\ \\ x=25$

You might be interested in

Happy Earth Day. Have a wonderful Day! If you answer you must give me ten Earth day Activities to answer. Thank you!

emmasim [6.3K]

Answer:

Happy Earth Day to u too.

Step-by-step explanation:

1) Plant a sapling

2) Draw a poster related to Earth Day

3) Color a picture of the Earth/ tree

4) Decorate ur room with plants

5) Prepare a speech on Earth Day

6) Do T-shirt designing with Earth as a design

7) Buy a paper/ cloth bag

8) Recycle what u use

9 Avoid plastic

10) Use bikes or walk instead of vehicles

5 0

3 years ago

Read 2 more answers

PLZ HELP IF WRONG ILL REPORT

dimulka [17.4K]

I HONESTLY WOULD THINK THIS COULD BE BIAS ONLY BECAUSE DIFFERENT OPINION ARE INCLUDED BUT AT THE SAME TIME BESTBUY NEVER SAID ANYTHING ABIUT THEM HATING BESTBUY

7 0

3 years ago

Read 2 more answers

What's a situation that can be represented by the opposite of -42

FromTheMoon [43]

| 42 | The absolute value of forty two

8 0

3 years ago

Read 2 more answers

Please help!! Write in simplest radical form: √7/8 Show how you figured it out

12345 [234]

Given expression: $\sqrt{\frac{7}{8}}$ .

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{\frac{a}{b}}=\frac{\sqrt[n]{a}}{\sqrt[n]{b}}$

$=\frac{\sqrt{7}}{\sqrt{8}}$

$\sqrt{8}=\sqrt{2^2\cdot \:2}=2\sqrt{2}$

$\frac{\sqrt{7}}{\sqrt{8}} =\frac{\sqrt{7}}{2\sqrt{2}}$

$\mathrm{Rationalize\:}\frac{\sqrt{7}}{2\sqrt{2}}$

$\mathrm{Multiply\:by\:the\:conjugate}\:\frac{\sqrt{2}}{\sqrt{2}}$

$=\frac{\sqrt{7}\sqrt{2}}{2\sqrt{2}\sqrt{2}}$

$=\frac{\sqrt{14}}{4}$

$=\frac{\sqrt{14}}{4}$ .

3 0

3 years ago

Can someone plz help me. How can you find the inequalities of 11/15 and 5/7. Next 5/9 and 7/13. Next 11/15 and 5/7. Lastly 5/9 a

LekaFEV [45]

To make this a little clearer, let's give the pairs of inequalities the same denominator:

Question 1:
 $\frac{11}{15}$ ? $\frac{5}{7}$
First, apply the common denominator to the first fraction:
$(\frac{11}{15})7 \\ \frac{11}{15} * \frac{7}{7} \\ \frac{11*7}{15*7} \\ \frac{77}{105}$
Do the same for the second: $15( \frac{5}{7}) \\ \frac{5}{7}* \frac{15}{15} \\ \frac{5*15}{7*15} \\ \frac{75}{105}$
Nest, compare the two fractions:
$\frac{77}{105} \ \textgreater \ \frac{75}{105}$
Therefore:
$\frac{11}{15}$ > $\frac{5}{7}$

Question Two:
$\frac{5}{9}$ ? $\frac{7}{13}$
Apply the common denominator to fraction one:
$13( \frac{5}{9}) \\ \frac{5}{9} * \frac{13}{13} \\ \frac{5*13}{9*13} \\ \frac{65}{117}$
Fraction two:
$9(\frac{7}{13}) \\ \frac{7}{13} * \frac{9}{9} \\ \frac{7*9}{13*9} \\ \frac{63}{117}$
Evaluate:
$\frac{65}{117}$ > $\frac{63}{117}$
Therefore:
 $\frac{5}{9}$ > $\frac{7}{13}$

Hope this helps!

5 0

3 years ago