Answer:
64
Explanation:
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<span>a. 0.325 g / 63.55 g/mol = 5.11 X 10^-3 moles Cu. SHould form 5.11 X 10^-3 mol Cu2+
b. Should form 5.11 X 10^-3 mol Cu(OH)2
c. 1 g Zn / 65.4 g/mol = 0.0153 mol Zn
Excess Zn = 0.0153 - 0.0051 = 0.0102 moles excess zinc
d. 5.11 X 10^-3 mol Mg X 24.3 g/mol = 0.124 grams Mg</span>
Explanation:
The answer for this question depends on the type of meniscus in the cylinder. If it is an upright meniscus like in water, the reading should be taken at the bottom of the meniscus. However if it is an inverted meniscus like in mercury, the reading should be taken at the top of the meniscus.
(Can you check and see if there's any pictures or information that is missing?)
The balanced reaction would be as follows:
<span>3NaOH + H3PO4 --> Na3PO4 + 3H20
We are given the concentration and the amount of the reactants to be used. We use these values for the calculations as follows:
</span><span>How many mL of .225 M NaOH will react with 4.568g H3PO4?
4.568 g (1 mol / 98 g) ( 3 mol NaOH / 1 mol H3PO4 ) ( 1 L / .225 mol NaOH ) = 0.621 L or 621 mL of .225 NaOH</span>
Answer:
Piso = 32.17 Torr
Pprop = 5.079 Torr
yprop = 0.1364
yiso = 0.8636
Explanation:
From the question; we can opine that :
- The mole fraction of isopropanol in a mixture of isopropanol and propanol will be 1.
-
The partial pressure of isopropanol will be its mole fraction multiplied by vapor pressure of isopropanol
-
The partial pressure of propanol will be its mole fraction multiplied by vapor pressure of propanol
-
In the vapor, the mole fraction of propanol will be its partial pressure divided by the sum of the two partial pressures
NOW;
When xprop = 0.243; xisopropanol will be 1- 0.243 = 0.757
P°iso = 45.2 Torr at 25 °C so
Piso will be 45.2 × 0.757 = 32.17 Torr
Pprop will be 20.9 × 0.243 = 5.079 Torr
yprop = 5.079/(5.079 +32.17) = 0.1364
yiso = 1-0.1364 = 0.8636
