The correct structure of the question is as follows:
The function f(x) = x^3 describes a cube's volume, f(x) in cubic inches, whose length, width, and height each measures x inches. If x is changing, find the (instantaneous) rate of change of the volume with respect to x at the moment when x = 3 inches.
Answer:
Step-by-step explanation:
Given that:
f(x) = x^3
Then;
V = x^3
The rate whereby V is changing with respect to time is can be determined by taking the differentiation of V
dV/dx = 3x^2
Now, at the moment when x = 3;
dV/dx = 3(3)^2
dV/dx = 3(9)
dV/dx = 27 cubic inch per inch
Suppose it is at the moment when x = 9
Then;
dV/dx = 3(9)^2
dV/dx = 3(81)
dV/dx = 243 cubic inch per inch
The figure is a parallelogram, and in a parallelogram, the lower side and the upper side have the same length. Also, the left side and the right side have the same length. This is shown in the following image:
The red sides are equal, and the blue sides are equal.
Thus, since the blue sides are equal, we can use the following equation to find x:
And since, once we know x, we can know the length of JK, this is the equation that we can use to find JK.
Answer:
7x=3x+14
Answer:
75%
Step-by-step explanation:
we know that 60% of x is 120. we can rewrite this to .6x = 120, to get x we divide both sides by .6, so x = 200. now 120 + 30 = 150. then we divide 150 out of 200 which is .75 it 75%
Answer:
3x-11
Step-by-step explanation:
f (x) = 3x - 5
f(x-2)
Replace x in the function with x-2
f (x-2) = 3(x-2) - 5
=3x-6 -5
=3x-11
