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2 years ago

Twice the difference of a number and 5 is 2. Use the variable W for the unknown number

1 answer:

8 0

Hey there!

The difference of a number, w, and 5 will be represented by (w – 5). Twice this would simply multiply this expression by 2, making it 2(w – 5). Finally, just set this expression equal to 2. Your equation is 2(w – 5) = 2.

To solve this, expand the two to the terms in parentheses. Then, solve the rest of the way as you would normally, using addition, subtraction, multiplication, or division to cancel out and move around terms. Remember, what you do on one side must be done to the other!

2(w – 5) = 2
(2*w – 2*5) = 2
(2w – 10) + 10 = (2) + 10
(2w) ÷ 2 = (12) ÷ 2
w = 6

Hope this helped you out! :-)

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Can someone tell me what is the slope of the line that includes points (4,-10) and (6,8)

miss Akunina [59]

Answer: hmmm no!

Step-by-step explanation:

3 0

2 years ago

jan, mya, and Sara ran a total of 64 miles last week. jan and mya ran the same number of miles. Sara ran 8 less miles than mya.

Debora [2.8K]

So,

We'll just use A to represent both Jan and Mya's miles, since they ran the same number.

We have the equations:
1. Jan (J) = Mya (M)
2. Sara (S) = M - 8
3. 2A + S = 64
J = M
S = M - 8

We'll just use A to represent both J and M.

S = M - 8

We'll use Elimination by Substitution.
2A + A - 8 = 64

Collect Like Terms
3A - 8 = 64

Add 8 to both sides
3A = 72

Divide both sides by 3
A = 24

Since
A = J
and
A = M
and
J = M
then
J = 24
M = 24

Substitute
S = 24 - 8
S = 16

Check
24 + 24 + 16 = 64
64 = 64 This checks.

So,
J = 24
M = 24
S = 16

4 0

3 years ago

Read 2 more answers

Rebecca is a Texas resident and she plans to attend Texas Tech for all 4 years of college. She has a yearly scholarship of $10,0

andrezito [222]

Answer:

To complete the required $m dollars for her college, she needs $(m - 60,000).

Step-by-step explanation:

Suppose Rebecca needs $m to complete her college education,

because she has a yearly scholarship of $10,000, she would have $10,000 × 4 = $40,000 for the four years she would spend in college.

Together with her savings of $20,000, she has $20,000 + $40,000 = $60,000 in total.

Therefore to complete the required $m dollars for her college, she needs $(m - 60,000).

5 0

2 years ago

Consider an m-by-n chessboard with m and n both odd. To fix the notation, suppose that the square in the upper left-hand corner

beks73 [17]

There are two cases to consider.

A) The removed square is in an odd-numbered column (and row). In this case, the board is divided by that column and row into parts with an even number of columns, which can always be tiled by dominos, and the column the square is in, which has an even number of remaining squares that can also be tiled by dominos.

B) The removed square is in an even-numbered column (and row). In this case, the top row to the left of that column (including that column) can be tiled by dominos, as can the bottom row to the right of that column (including that column). The remaining untiled sections of the board have even numbers of rows, so can be tiled by dominos.

_____

Perhaps the shorter answer is that in an odd-sized board, the corner squares are the ones that there is one of in excess. Cutting out one that is of that color leaves an even number of squares, and equal numbers of each color. Such a board seems like it <em>ought</em> to be able to be tiled by dominos, but the above shows there is actually an algorithm for doing so.

7 0

2 years ago

What is the value of the expression i 0 × i 1 × i 2 × i 3 × i 4?

astraxan [27]

ANSWER

The value of the expression is
$- 1$

EXPLANATION

Method 1: Rewrite as product of
${i}^{2}$

The expression given to us is,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4}$

We use the fact that
${i}^{2} = - 1$
to simplify the above expression.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{1} \times {i}^{3} \times {i}^{2} \times {i}^{4}$

This implies,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2} \times {i}^{2}$

We substitute to obtain,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times - 1 \times - 1 \times - 1\times - 1 \times - 1$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = 1\times 1 \times 1 \times - 1 = - 1$

Method 2: Use indices to solve.

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{0 + 1 + 2 + 3 + 4}$

This implies that,

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = {i}^{10}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( {{i}^{2}} )^{5}$

${i}^{0} \times {i}^{1} \times {i}^{2} \times {i}^{3} \times {i}^{4} = ( - 1 )^{5} = - 1$

8 0

3 years ago

Read 2 more answers