Explanation:
When plutonium - 239 undergoes an alpha decay, it produces uranium - 235 in the process.
A radioactive occurs when a nuclide spontaneously disintegrates due to instability to produce lighter atoms which the release of radiation and energy.
²³⁹₉₄Pu ⇒ ²³⁵₉₂U + ⁴₂He + energy
In a nuclear reaction, the mass and atomic numbers must always remain conserved. Nuclear reactions do not obey the law of conservation of matter and mass.
The mass number are the superscript before the symbol of the nuclide
The atomic number is the subscript.
The sum of the atomic number on the left hand side equals that on the right hand side. This goes for the mass number too.
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Balanced nuclear equation brainly.com/question/10094982
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Answer:
düz devam sağa dön bı tane Kabe var
Answer:
B. 0 degrees
Explanation:
The magnetic flux through a certain area enclosed by a loop of wire immersed in a region with magnetic field is given by:
where
B is the strength of the magnetic field
A is the area enclosed by the coil
is the angle between the direction of the magnetic field and the direction of the normal to the coil
From the equation above, we see that the magnetic flux is maximum when
So when the field is parallel to the normal to the coil (so, when it is perpendicular to the coil), therefore when:
So, the correct option is
B. 0 degrees
Answer:
Time is 14.8 s and cannot landing
Explanation:
This is a kinematic exercise with constant acceleration, we assume that the acceleration of the jet to take off and landing are the same
Calculate the time to stop, where it has zero speed
Vf² = Vo² + a t
t = - Vo² / a
t = - 110²/(-7.42)
t = 14.8 s
This is the time it takes to stop the jet
Let's analyze the case of the landing at the small airport, let's look for the distance traveled to land, where the speed is zero
Vf² = Vo² + 2 to X
X = -Vo² / 2 a
X = -110² / 2 (-7.42)
X = 815.4 m
Since this distance is greater than the length of the runway, the jet cannot stop
Let's calculate the speed you should have to stop on a track of this size
Vo² = 2 a X
Vo = √ (2 7.42 800)
Vo = 109 m / s
It is conclusion the jet must lose some speed to land on this track
