Answer: 6m/s
Explanation:
Using the law of conservation of momentum, the change in momentum of the bodies before collision is equal to the change in momentum after collision.
After collision, the two objects will move at the same velocity (v).
Let mA and mB be the mass of the two objects
uA and uB be their velocities before collision.
v be their velocity after collision
Since the two objects has the same mass, mA= mB= m
Also since object A is at rest, its velocity = 0m/s
Velocity of object B = 12m/s
Mathematically,
mAuA + mBuB = (mA+mB )v
m(0) + m(12) = (m+m)v
0+12m = (2m)v
12m = 2mv
12 = 2v
v = 6m/s
Therefore the speed of the composite body (A B) after the collision is 6m/s
Answer:
a) x₀ = - 2 m , b) y = 4.47 m
Explanation:
A wave travels in the middle with constant speed, let's use the equation of uniform motion
v = d / t
t = d / v
The distance to the first listeners, see attached
d₁ = x₀-x
t = (x₀ +7) / v
The distance to the second listener
d₂ = x - x₀
t = (+ 3- x₀) / v
As the wave arrives at the same time, we can equal the two equations
(x₀ +7) / v = (3 -x₀) / v
x₀ + 7 = 3 - x₀
2 x₀ = 3 - 7
x₀ = -4/2
x₀ = - 2 m
b) The time it takes for the wave to reach the listeners of the x-axis, where the speed of sound is 340 m / s
t = 5/340
t = 0.0147 s
Let's look for the distance the wave travels for the listener axis and
v = d₃ / t
d₃ = v.t
d₃ = 340 * 0.0147
d₃ = 5 m
For the distance component we use the Pythagorean triangle
d₃² = x₀² + y²
y² = d₃² - x₀²
y = √ (d₃² -4)
y = √ (5² -4)
y = 4.47 m
Answer:
104.3 cm or 179.7
Explanation:
First find time that it takes for the object to hit the ground
*
Then find xf of projectile 
not 100% sure if the projectile is going away from the object or towards it but you either do 142- 37.7 or 142+37.7
hope that helps
Complete Question
The complete question is shown on the
Answer:
The ascending order would be 2nd < 1st < 3rd
Explanation:
Generally the the Normal force is mathematically represented as
=> 
For the first drawing the value 
is between that of the the second and the third drawing so the Normal force would also be between the normal forces of the second and the third drawing
For the second drawing whose value of is less than that of the first and the third the normal force would also be less than that of the first and third
For the the third drawing whose value is (90°) which is higher than the first and the second the normal force would also be higher than the first and the second
Answer: they could get a piece of the coral and run tests on it
Explanation:
