Answer:
No.
Explanation:
There is no change in gravitational force based on the sizes remaining the same. If there was a change in gravitational force the orbits of all planets would change.
This sounds pretty easy, in fact. The orbital motion can be assumed to be circular and with constant speed. Then, the period is the time to do one revolution. The distance is the length of a revolution. That is 2*pi*R, where R is the distance between the Moon and the Earth (the respective centers to be precise). In summary, it's like a simple motion with constant speed:
v = 2*pi*R/T,
you have R in m and T is days, which multiplied by 86,400 s/day gives T in seconds.
Then v = 2*pi*3.84*10^8/(27.3*86,400) = 1,022.9 m/s ~ 1 km/s (about 3 times the speed of sound :)
For the Earth around the Sun, it would be v = 2*pi*149.5*10^9/(365*86,400)~ 29.8 km/s!
I know it's not in the problem, but it's interesting to know how fast the Earth moves around the Sun! And yet we do not feel it (that's one of the reasons some ancient people thought crazy the Earth not being at the center, there would be such strong winds!)
Answer:
At twice the distance, the strength of the field is e/4
Explanation:
F = the strength of an electric field.
F is inversely proportional to the squared distance from the point charge.
mathematically,
F = k(e/d²)
hence, if d is doubled,keeping other forms constant
F = e/4,
Using the formula t=root of 2h/g then where h=28 and g=9.8 then substitute so the answer is 2.4seconds
