The latitude of any location on earth is the angle formed by the two rays drawn from the center of earth to the location and to
the equator. the ray through the location is the initial ray. use 3960 miles as the radius of the earth. suppose city a is due north of city
b. find the distance between city a (north latitude 45 degrees 28 prime upper n45°28′ n) and city b (latitude 38 degrees 52 prime upper n38°52′ n).
b. find the distance between city a (north latitude 45 degrees 28 prime upper n45°28′ n) and city b (latitude 38 degrees 52 prime upper n38°52′ n).
1 answer:
The distance between city a and city b is 833.345 miles.
We know that
1°=60'
The distance of city a from the initial ray is calculated as
x_a=3960*tan45.46°=4024.101 miles
The distance of city b from the initial ray is calculated as
x_b=3960*tan 38.86°=3190.75 miles
Now the distance between city a and b is equal to
4024.101-3190.75=833.345 miles
This is the vertical distance between the cities.
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The equation to find the period of oscillation.
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On substituting the values of the length of the pendulum and the acceleration due to gravity at the point where the period of the pendulum is being measured, the above equation yields the value of the period of the pendulum.
Final answer:
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Answer:
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