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Sphinxa [80]
3 years ago
10

The latitude of any location on earth is the angle formed by the two rays drawn from the center of earth to the location and to

the equator. the ray through the location is the initial ray. use 3960 miles as the radius of the earth. suppose city a is due north of city
b. find the distance between city a​ (north latitude 45 degrees 28 prime upper n45°28′ n​) and city b​ (latitude 38 degrees 52 prime upper n38°52′ n​).

Physics
1 answer:
Alina [70]3 years ago
5 0

The distance between city a and city b is 833.345 miles.

We know that

1°=60'

The distance of city a from the initial ray is  calculated as

x_a=3960*tan45.46°=4024.101 miles

The distance of city b from the initial ray is calculated as

x_b=3960*tan 38.86°=3190.75 miles

Now the distance between city a and b is equal to

4024.101-3190.75=833.345 miles

This is the vertical distance between the cities.

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kramer

Answer:

The height reached by the material on Earth is 91 km.

Explanation:

Given that,

Mass M_{Io}=8.93\times10^{22}\ kg

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Suppose we need to find that how high would this material go on earth if it were ejected with the same speed as on Io?

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g =\dfrac{GM_{Io}}{(R_{Io})^2}

Put the value into the formula

g=\dfrac{6.67\times10^{-11}\times8.93\times10^{22}}{(1821\times10^{3})^2}

g=1.79\ m/s^2

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H=\dfrac{v^2}{2g}

Using ratio of height of earth and height of Io

\dfrac{H_{e}}{H_{Io}}=\dfrac{\dfrac{v^2}{2g_{e}}}{\dfrac{v^2}{2g_{Io}}}

\dfrac{H_{e}}{H_{Io}}=\dfrac{g_{Io}}{g_{e}}

Put the value into the formula

\dfrac{H_{e}}{H_{Io}}=\dfrac{1.79}{9.8}

\dfrac{H_{e}}{H_{Io}}=0.182

H_{e}=0.182\times H_{Io}

H_{e}=0.182\times500

H_{e}=91\ km

Hence, The height reached by the material on Earth is 91 km.

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Answer:

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the formula relates the time, t, in seconds for a pendulum with the length, l, in feet, to make one full swing back and forth. w
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This shows that the length of a pendulum that makes one full swing in 2.2 seconds is 392.71 feet.

Given the formula for calculating the length of the pendulum expressed as:

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T is the period of the pendulum

Given the following parameters:

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Substitute the given parameters into the formula will give;

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So, this shows that the length of a pendulum that makes one full swing in 2.2 seconds is 392.71 feet.

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A hummingbird flies 2.0 m along a straight path at a height of 5.3 m above the ground. Upon spotting a flower below, the humming
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To solve this problem we will apply the concepts of Pythagoras to find the net path. An easy way is to graph the path to trace the path, which resembles that of a right triangle. The information provided is equivalent to that of the two short sides of the triangle, so we will find the longest side by the Pythagorean theorem. In this way,

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