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soldier1979 [14.2K]
3 years ago
13

In the year 1178, five monks at Canterbury Cathedral in England observed what appeared to be an asteroid colliding with the moon

, causing a red glow in and around it. It is hypothesized that this event created the crater Giordano Bruno, which is right on the edge of the area we can usually see from Earth.
Physics
2 answers:
Contact [7]3 years ago
7 0

Complete Question

In the year 1178, five monks at Canterbury Cathedral in England observed what appeared to be an asteroid colliding with the moon, causing a red glow in and around it. It is hypothesized that this event created the crater Giordano Bruno, which is right on the edge of the area we can usually see from Earth.

How long after the asteroid hit the Moon,which is 3.84 *10^5 km away ,would the light first arrive on the earth in seconds

Answer:

The time it would take is  t = 1.28 \ sec

Explanation:

The objective of this question is to obtain the time the light would arrive earth

      We are told that the distance from moon to  earth is  

                  D = 3.84*10^5km = 3.84*10^5 * 1000 = 3.84*10^8m

Now generally time is mathematically represented as

                          t = \frac{D}{c}

The c here is the speed of light which has a value of c = 3*10^8 m/s

        Now substituting values

                        t = \frac{3.84 * 10^8 }{3*10^8}

                           = 1.28 \ sec

antiseptic1488 [7]3 years ago
4 0

Answer:

Incomplete question: The question is: How logn after the asteroid hit the Moon, which is 3.84x10⁵km away, would the light first arrive on Earth in seconds?

The answer is 1.28 s

Explanation:

Data given:

d = distance = 3.84x10⁵km = 3.84x10⁸m

v = velocity of light = 3x10⁸ m/s

The time will be:

t=\frac{d}{v} =\frac{3.84x10^{8} }{3x10^{8} } =1.28s

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A proton is located at <3 x 10^-10> m. What is r, the vector from the origin to the location of the proton
Eduardwww [97]

Complete Question

A proton is located at <3 x 10^{-10}, -5*10^{-10}  , -5*10^{-10}> m. What is r, the vector from the origin to the location of the proton

Answer:

The  vector position is   \=r=

Explanation:

From the question we are told that

  The  position of the proton is m

Generally the vector location of the proton is mathematically represented as

       \= r =

So substituting values

     \=r=

4 0
3 years ago
Compared to its weight on Earth, a 5kg object on the moon will weigh
shutvik [7]

Answer:

8.1 N/49 N=0.1653  which means 16.53% of the weight of the object on Earth.

Explanation:

On the Moon, where the gravitational constant is 1.62 \frac{m}{s^2}, the weight of the 5 kg object will be: weight_M=m*g_M = 5 kg * 1.62 \frac{m}{s^2} =8.1 N

Where the answer is in Newtons (N) since all quantities are given in the SI system.

On Earth, on the other hand, the weight of the object is:

weight_E=m*g_E= 5 kg* 9.8 \frac{m}{s^2} = 49N

Therefore the object's weight on the Moon compared to that on Earth will be:

8.1N/49N=0.1653

That is, 16.53% of the weight the object has on Earth.

5 0
3 years ago
The three notches in the graph occur where the driver changed gears. Describe the changes in velocity and acceleration of the ca
kaheart [24]
<h3>Answer : </h3><h3 /><h3>A ) The larger gear can be moved by applying a relatively small force on the smaller gear.</h3>

<h3>B ) The force applied on the smaller gear is transmitted without any loss to the larger gear .</h3><h3 /><h3>C ) the direction of motion can be changed without changing the direction of the applied force .</h3>

D ) the system would continue to move without any further, after and initial force has set in motion.

6 0
3 years ago
What is the mean of 22, 72, 79, 72, and 70
Nataly_w [17]

Answer:

63

Explanation:

You first have to add all the numbers together.

22+72+79+72+70 = 315

You divide the total by the amount of numbers (5)

315/5 = 63

The mean is 63

7 0
3 years ago
What are the average velocity and average acceleration of the tip of a 2.4 cm long hour hand of a clock?
ra1l [238]
A circle has a revolution of 360°. Since there are 12 hour markings, each hour interval has an angle of 30°. In radians, that would be equal to π/6 radians. So, in every 1 hour that passes, it covers π/6 of an angle. So, the angular velocity denoted as ω is π/6 ÷ 1 hour = π/6 rad/h. We can compute the average linear velocity, v, from the relationship:

v = rω, where r is the radius of the circle which is the length of the hour hand
v = (2.4 cm)(π/6 rad/h)
v = 1.257 cm/hour

Therefore, the average velocity is 1.257 cm per hour.

For the average acceleration, it is equal to zero. The hands of the clock move at a constant velocity. Since acceleration is the change of velocity per unit time, there is no change of velocity because it's constant. That's why it is zero.

8 0
3 years ago
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